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3 years ago

If f(x)=4x-3,what is f(x)^-1 ?

Mathematics

1 answer:

Igoryamba3 years ago

5 0

Answer:

For future students, the answer is x+3/4. I am taking my semester exam, and got this question right.

pls mark brainli est i need the crowns for the next level

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A bank made a farmer loan of $1,000 at 14% for 3 years compounded annually. Find the future value and the compound interest paid

Anna11 [10]

Answer:

Principal = $1,000

Rate of interest = 14% = 0.14

Time = 3 years

$A= P(1+r)^t$

A = Amount or future value

P = Principal

r = rate of interest in decimals

t = time

Substitute the values in the formula

$A= 1000(1+0.14)^3$

$A=1481.544$

Future Value is $1481.544

Compound interest = Amount - Principal = $1481.544- $1000 = $481.544

Formula of simple interest : $SI =\frac{P \times R \times T}{100}$

Substitute the values :

$SI =\frac{1000 \times 14 \times 3}{100}$

$SI =420$

So, Simple interest = $420

Compound interest - Simple interest

= $481.544- $420

= $61.544

So, Compound Interest is $61.544 more than simple interest.

8 0

3 years ago

There are 10 counters in a bag: 3 are red, 2 are blue and 5 are green. The conents of the bag are shaken before Maxine randomly

luda_lava [24]

The probability is 3/20

7 0

3 years ago

The number of chocolate chips in an 18-ounce bag of chocolate chip cookies is approximately normally distributed with mean 1252

dangina [55]

Answer:

Um I think it is 120%, but i am not totalyy sure

3 0

2 years ago

Factor the expression completely. 1/4x + 19/4

puteri [66]

Answer: i think it is... x = -19

8 0

3 years ago

What are the potential solutions to the equation 2ln(x+3)=0

skad [1K]

$2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1$

Expanding the left side gives

$x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0$

which gives two solutions, $x=-4$ and $x=-2$ . But if $x=-4$ , then $\ln(x+3)=\ln(-1)$ , but this number isn't real, so $x=-4$ is an extraneous solution. Meanwhile if $x=-2$ , you get $\ln(-2+3)=\ln1=0$ , so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.

4 0

3 years ago

Read 2 more answers