The midpoint of (x1,y1) and (x2,y2) is

just average them
(4,1) and (-2,4)
the midpoint is

(1,-1.5)
Answer:
true
Step-by-step explanation:
a square will always be a rectangle but a rectangle will not always be a square.
If it's just distribution, not solving for s (I mean I could but do you need to?):
5(2s² - 3s + 4) Distribute/multiply 5 into (2s² - 3s + 4)
(5)2s² - (5)3s + (5)4
10s² - 15s + 20