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jek_recluse [69]
3 years ago
9

The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 15.4 V and b = -5.10 V/m.

Mathematics
1 answer:
Minchanka [31]3 years ago
7 0

Answer:

V(0)=15.4\\V(3)=0.1\\V(6)=-15.2

Step-by-step explanation:

The potential in a region between x = 0 and x = 6.00 m is V = a + bx.

Put a = 15.4 V and b = -5.10 V/m.

So, V=15.4-5.10x

To find: Potential at x =0, 3, 6

Solution:

Potential at x = 0:

V=15.4-0=15.4

Potential at x = 3:

V=15.4-5.10(3)=15.4-15.3=0.1

Potential at x = 6:

V=15.4-5.10(6)=15.4-30.60=-15.2

Therefore,

V(0)=15.4\\V(3)=0.1\\V(6)=-15.2

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