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3 years ago

The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 15.4 V and b = -5.10 V/m.

Mathematics

1 answer:

Minchanka [31]3 years ago

7 0

Answer:

$V(0)=15.4\\V(3)=0.1\\V(6)=-15.2$

Step-by-step explanation:

The potential in a region between x = 0 and x = 6.00 m is V = a + bx.

Put a = 15.4 V and b = -5.10 V/m.

So, $V=15.4-5.10x$

To find: Potential at x =0, 3, 6

Solution:

Potential at x = 0:

$V=15.4-0=15.4$

Potential at x = 3:

$V=15.4-5.10(3)=15.4-15.3=0.1$

Potential at x = 6:

$V=15.4-5.10(6)=15.4-30.60=-15.2$

Therefore,

$V(0)=15.4\\V(3)=0.1\\V(6)=-15.2$

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