(1)1.3t^3 +t^2 -42t +8
(2)1.3t^3 + t^2 -6t +8
(3)1.9 t^3.+ 8.4^t^2 -42t
(4)1.9t^2 -42t + 8
I hope I got that right!!
okay, now they are all separated in columns, add the ones with the same powers (e.g (1)_ 1.3t^3 + (2) 1.3t^3 + (3) 1.9 t^3 = 4.5t^3.
No, the two rectangles are not similar. Similar rectangles will have the same ratio of shortest to longest side lengths.
3 : 4 ≠ 5 : 6
Answer:
y ≥ x^2 - 1
Step-by-step explanation:
First, we can see that the shaded region is above what seems to be a parabola, and we also can see that the lines of the parabola are solid lines (which means that the points on the curve itself are solutions, so the symbol ≥ is used)
Then:
y ≥ a*x^2 + b*x + c
where a*x^2 + b*x + c is the general quadratic equation.
Now let's find the equation for the parabola:
f(x) = a*x^2 + b*x + c
We also can see that the vertex of the parabola is at the point (0, -1)
This means that:
f(0) = -1 = a*0^2 + b*0 + c
= -1 = c
then we have that c = -1
Then:
f(x) = a*x^2 + b*x - 1
Now we can look at the graph again, to see that the zeros of the parabola are at +1 and -1
Which means that:
f(1) = 0 = a*1^2 + b*1 - 1 = a + b - 1
f(-1) = 0 = a*(-1)^2 + b*(-1) - 1 = a - b - 1
Then we got two equations:
a + b - 1 = 0
a - b - 1 = 0
from this we can conclude that b must be zero.
Then:
b = 0
and these equations become:
a - 1 = 0
a - 1 = 0
solving for a, we get:
a = 1
Then the quadratic equation is:
f(x) = 1*x^2 + 0*x - 1
f(x) = x^2 - 1
And the inequality is:
y ≥ x^2 - 1
The answer to the question is c
Answer:
x = 3
Step-by-step explanation:
The external angle of a triangle is equal to the sum of the 2 opposite interior angles.
10x + 2 is an exterior angle of the triangle, thus
10x + 2 = 2x + 1 + 25
10x + 2 = 2x + 26 ( subtract 2x from both sides )
8x + 2 = 26 ( subtract 2 from both sides )
8x = 24 ( divide both sides by 8 )
x = 3