Answer:
the answer is the mean
Step-by-step explanation:
you add all the numbers then divide by how many you have
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
It lies between 10 and 11<span />
Answer:
21 degrees
Step-by-step explanation:
To find this, we are going to use the appropriate trigonometric ratio
The right angle faces the length 22 which is the hypotenuse
The marked angle faces the length 8 which makes it the opposite
The trigonometric ratio that links the two is the sine
The sine is the ratio of the opposite to the hypotenuse
So, we have it that;
sine ? = 8/22
? = arc sine 8/22
? = 21 degrees
Answer:
1.E
2.H
3.F
4.D
5.A
6.G
7.B
8.C
Step-by-step explanation:
