All categories

3 years ago

List the numbers that have 30 as a multiple

1 answer:

3 0

First we list the multiples of each number.
multiples of 5 are 10,15,20,25,30,35,40,...
multiples of 6 are 12,18,24,30,36,42,48,...
multiples of 15 are 30,45,60,75,90,...
now, when you look at the list of multiples, you can see that 30 is the smallest number that appears in each list.
therefore, the least common multiple of...... 5,6 and 15 is 30.

You might be interested in

Plz help me with this

madreJ [45]

In order a0->a5: 1/3, 1, 3, 9, 27, 81

All you're doing is plugging the x-value in. So for a2, x=1, so y=3¹ which means y=3.

6 0

3 years ago

Read 2 more answers

There are four different kinds of animals on the farm.There is a different number of each kind of animal. There are 19 more cows

dimaraw [331]

You need the total amount of how many animals

4 0

3 years ago

You deposit $6000 in an account earning 2% interest compounded monthly. How much will you have in your account in 15 years?

Dmitrij [34]

Well 2% of 6000 is 120. Then u take 120 times 12 (the amount of months in 1 year) than u take the answer (1440) and mulitply it by 15 (the amount of years) and get <span>21600.

Hope this helps! :3
</span>

4 0

3 years ago

If 20 divided by 5 = 4 <br> Then 20 divided by 5.5=4.?

ahrayia [7]

Answer:

Step-by-step explanation:

20 divided by 5.5 is a decimal 3.63

3 0

3 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

$x^3y'' + 2x^2y' + 4y$

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ; $x=x_o$ is located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

$y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0$

$y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0$

The standard form of the differential equation is :

$\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0$

Thus;

$P(x) = \dfrac{2}{x}$

$Q(x) = \dfrac{4}{x^3}$

The zeros of $x,x^3$ is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x) and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = $x*\dfrac{2}{x}$

p(x) = 2

q(x) = x²Q(x)

q(x) = $x^2 * \dfrac{4}{x^3}$

q(x) = $\dfrac{4}{x}$

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic at x = 0

$Q(x) = \dfrac{4}{x^3}$ do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0

3 years ago