Answer:
a)0.1714 b)0.504 c)0.5 d)0.2
Step-by-step explanation:
Total numbers between 1000 and 9999 (both inclusive)= 9000.
Probability=
a) Divisible by 5 and not by 7 means, that the number is divisible by 5 but not by 35.
Total numbers between 1000 and 9999 divisible by 5= 1800
Total numbers between 1000 and 9999 divisible by 35=257
Total numbers between 1000 and 9999 divisible by 5 but not by 35= 1800 - 257= 1543
Probability==0.1714
b) Finding the number of numbers with distinct digits,
We can find this by the method that how many digits can be placed in each place,
In the thousands place=9( 0 cannot be placed)
In the hundreds place=9( The digit inserted in the thousands place, cannot be put but 0 can be put now)
In the tens place=8( Numbers placed in hundreds and thousands place cannot be put)
In the ones place=7(The rest 3 numbers can't be put)
Total Favorable Outcomes=9 x 9 x 8 x 7 =4536
Probability==
=0.504
c) Total number of even numbers between 1000 and 9999= 4500
Probability==
=0.5
d) Total numbers between 1000 and 9999 divisible by 5= 1800
Probability= =
=0.2
Answer:
C
Step-by-step explanation:
We want to determine the vertex of the quadratic equation:
Recall that the vertex is given by the formulas:
In this case, <em>a</em> = -1, <em>b</em> = 2, and <em>c</em> = 1.
Determine the <em>x-</em>coordinate of the vertex:
To determine the <em>y-</em>coordinate, evaluate the function at <em>x</em> = 1:
In conclusion, the vertex of the quadratic equation is (1, 2).
Hence, our answer is C.
Answer:
Step-by-step explanation:
Hello!
You have the information for two variables
X₁: Number of consumer purchases in France that were made with cash, in a sample of 120.
n₁= 120 consumer purchases
x₁= 48 cash purchases
p'₁= 48/120= 0.4
X₂: Number of consumer purchases in the US that were made with cash, in a sample of 55.
n₂= 55 consumer purchases
x₂= 24 cash purchases
p'₂= 24/55= 0.4364
You need to construct a 90% CI for the difference of proportions p₁-p₂
Using the central limit theorem you can approximate the distribution of both sample proportions p'₁ and p'₂ to normal, so the statistic to use to estimate the difference of proportions is an approximate standard normal:
[(p'₁-p'₂) ± *
]
[(0.4-0.4364)±1.648 * ]
[-0.1689;0.0961]
The interval has a negative bond, it is ok, keep in mind that even tough proportions take values between 0 and 1, in this case, the confidence interval estimates the difference between the two proportions. It is valid for one of the bonds or the two bonds of the CI for the difference between population proportions to be negative.
I hope this helps!