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ANTONII [103]
3 years ago
5

The dimensions of an Olympic-sized swimming pool are 50 m long, 25 m wide, and the water is 2 m deep. What is the volume of wate

r?
Mathematics
2 answers:
il63 [147K]3 years ago
6 0
50 x 25 x 2=2500 cubic meters

aliina [53]3 years ago
5 0

Answer:

2500 m

Step-by-step explanation:

Mulitply 50, 25, and 2!

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A.
Lorico [155]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Price of home = $220,000

Down payment = 20%

3 points at closing

30 years fixed rate mortgage at 7%

A.)The down payment :

20% of price

0.2 × $220,000 = $44,000

B.) Amount of the Mortgage :

Price - down payment

$220,000 - $44,000 = $176,000

C.) Amount to be paid for the 3 point of closing :

3% of mortgage amount

0.03 * $176,000 = $5,280

D.) monthly payment :

(mortgage amount(1 + rate)) / 30* 12

176000(1 + 0.07)

($176,000 + $12320) / 360

$523

E.) Total cost of interest :

0.07 * 176000 = $12,320

8 0
3 years ago
What is the linear equation in standard form: 3x = -5y + 7
Licemer1 [7]

Answer:

<em><u>3x + 5y = 7</u></em>

Step-by-step explanation:

4 0
3 years ago
If f(x)=3|x-2|, what is f(5.9)? a: 9 b: 10 c: 11 d: 12
Mice21 [21]
|a|=  \left\{\begin{array}{ccc}a&if&a\geq0\\-a&if&a \ \textless \  0\end{array}\right\\\\f(x)=3|x-2|\\\\f(5.9)=3|5.9-2|=3|3.9|=3\cdot3.9=11.7
7 0
3 years ago
Read 2 more answers
An object moves along a coordinate axis so that its position at time t is given by s(t)=t3. Estimate its instantaneous velocity
Mademuasel [1]

If the position at time <em>t</em> is

<em>s(t)</em> = (1 m/s³) <em>t</em> ³

then the average velocity over <em>t</em> = 2 s and <em>t</em> = 2.001 s is

<em>v</em> (ave) = (<em>s</em> (2.001 s) - <em>s</em> (2 s)) / (2.001 s - 2 s)

<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)

<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)

<em>v</em> (ave) ≈ 12.006 m/s

6 0
2 years ago
Convert 3.212121… into a fraction using variable
seraphim [82]

Answer:

In fraction it is

\frac{3212121}{1000000}

<h2>#NoNeedFriends</h2>
3 0
2 years ago
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