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Sliva [168]
3 years ago
15

Please HELP! How do I factorise 2x^2 - 11x -6x please include working Thanks!

Mathematics
2 answers:
bekas [8.4K]3 years ago
7 0

Answer:

x(2x-17)

Step-by-step explanation:

2x^2-11x-6x\\2x^2-17x\\x(2x-17)


Steps:

Combine Like Terms (-11x and -6x)

Factor out the common term (x)


Harrizon [31]3 years ago
6 0

Answer:

x(2x-17)

Step-by-step explanation:

2x^2 -11x-6x

2x^2-17x

x is common

x(2x-17)


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3 0
3 years ago
Sebastian solved the radical equation y 1 = but did not check his solution. (y 1)2 = y2 2y 1 = –2y – 3 y2 4y 4 = 0 (y 2)(y 2) =
ale4655 [162]

Equation has no true solutions.

Given: y + 1 = \sqrt(-2y-3)\\

squaring both sides

{(y + 1)}^2  =-2y-3

{y}^2 + {1}^2+ 2y = -2y - 3

{y}^2+ 2y + 4 = 0

(y+2)(y+2) = 0

y = -2

TO VERIFY:

The law cos(x+90⁰)=-sin(x) can be proved by putting y=90⁰ in the following

Formula,

cos(x+y)=cos(x).cos(y)-sin(x).sin(y)

substitute value of y in equation

-2+1  =\sqrt(-2(-2)-3) gives:

-1 = 1 which is incorrect.

Therefore, There are no solutions to the equation.

Alternatively,

If (a1/a2) = (b1/b2) ≠ (c1/c2), then there will be no solution. This type of system of equations is called an inconsistent pair of linear equations. If we plot the graph, the lines will be parallel and system of equations have no solution.

To know more, visit:

brainly.com/question/14721094

#SPJ4

6 0
2 years ago
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