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Sliva [168]
3 years ago
15

Please HELP! How do I factorise 2x^2 - 11x -6x please include working Thanks!

Mathematics
2 answers:
bekas [8.4K]3 years ago
7 0

Answer:

x(2x-17)

Step-by-step explanation:

2x^2-11x-6x\\2x^2-17x\\x(2x-17)


Steps:

Combine Like Terms (-11x and -6x)

Factor out the common term (x)


Harrizon [31]3 years ago
6 0

Answer:

x(2x-17)

Step-by-step explanation:

2x^2 -11x-6x

2x^2-17x

x is common

x(2x-17)


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PLEASE HELP Show all Your work 25 points will give brainly
julsineya [31]

Answer:

x=9

Step-by-step explanation:

√117²=x²+6²

117=x²+36

x²=117-36

x²=81

x=9

6 0
4 years ago
a rectangle has a length of 9.00 inches with a width of 4.25 inches what is the area in square inches round to the correct signi
Helen [10]
Area = l x w
Area =9 x 4.25
A = 48.25
A≈ 48 in²
7 0
3 years ago
The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra
Snezhnost [94]
Let X denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by X_1,\ldots,X_{36}, each independently and identically distributed with distribution X_i\sim\mathcal N(26,7.2).

You want to find

\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)

Recall that if X\sim\mathcal N(\mu,\sigma), then the sampling distribution \overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right) with n being the size of the sample.

Transforming to the standard normal distribution, you have

Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}

so that in this case,

Z=6\dfrac{\overline X-26}{7.2}

and the probability is equivalent to

\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)
=\mathbb P(Z>1.481)\approx0.0693
5 0
3 years ago
Nvm i did it . it took me a long time but i did it
ra1l [238]
Wooooooo hoooooooo you goooooooo
                                          
                     
7 0
3 years ago
Evaluate the expression. 6 to the third power + 5( 8 + 15)
olya-2409 [2.1K]

Answer:

5083

Step-by-step explanation:

6^3 + 5(8 + 15)

Simplify the bracket first

6 x 6 x 6 + 5 (23)

216 + 5 (23)

221 (23)

221 x 23 = 5083

6 0
3 years ago
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