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horsena [70]
3 years ago
14

Quadrilateral JKLM has vertices J(–7, –2), K(–2, –2), L(–3, –4), and M(–6, –4). Find the midpoints of each of the sides JM andKL

.
Mathematics
2 answers:
wel3 years ago
8 0
To find the midpoint of a segment (or the midpoint between two points - here the endpoints of the side) we use the midpoint formula. What it comes down to is finding the "average" of the x-coordinate and the "average" of the y-coordinate.

The formula is as follows. The midpoint of the segment with endpoints (x_{1} ,y_{1}) and (x_{2} ,y_{2}) is given by ( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Let us find the midpoint of side JM. It does not matter which point we designate with the 1s and which we designate with the 2s so let's let J (-7,2) = (x_{1} ,y_{1}) and M (-6,-4) = (x_{2} ,y_{2}).

Now we plug these into the formula as follows: ( \frac{-7+-6}{2},\frac{-2+-4}{2}) = ( \frac{-13}{2},\frac{-6}{2})=(-6.5,-3)

Let us now find the midpoint of side KL. It does not matter which point we designate with the 1s and which we designate with the 2s so let's let K (-2,-2) = (x_{1} ,y_{1}) and L (-3,-4) = (x_{2} ,y_{2})

Now we plug these into the formula as follows: ( \frac{-2+-3}{2},\frac{-2+-4}{2}) = ( \frac{-5}{2},\frac{-6}{2})=(-2.5,-3)


Rudiy273 years ago
3 0
We calculate the midpoint by taking the average of the x- and y-coordinates of both points. For side JM, with point J(-7, -2) and point M(-6, -4), we average the x-coordinates to get (-7 - 6) / 2= -13/2, and the y-coordinates average to (-2 - 4) / 2 = -3. So the midpoint of side JM is (-13/2, -3).
The calculation is similar for side KL: (-2 - 3) / 2 = -5/2, and (-2 - 4) / 2 = -3, so the midpoint of side KL is (-5/2, -3).
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In Example 3, the track has 6 lanes that are each 1 meter in width. a. What is the outer perimeter of the track? Round your answ
son4ous [18]

Answer:

Incomplete question, check attachment for the necessary diagram

Step-by-step explanation:

Note in the attachment,

We have two identical straight line of lenght

L1 = L2 = 84.39m

We also have two identical semicircle or radius 36.5m to the first track lane

But this is not the radius of the circle, the radius of the circle will now be 36.5 plus the 6 track lane and we are told that one track lane is 1m, then, the track lane is 6m

So, radius = 36.5+6

r = 42.5m

Then, we need to calculate the perimeter of the semicircle using the formula of perimeter of a circle and dividing by2

P = 2πr/2

P =πr

P = 22/7 × 42.5

P = 133.57 m

Then, the arc 1 is equal to arc 2 which is equal to 133.57 m

A1 = A2 = 133.57 m

Now we have all the dimensions,

Then, the perimeter can be calculated by adding the length of the sides

The perimeter of the field = Lenght of the two straight lines plus the length of the two semicircle arc

P = L1 + L2 + A1 + A2

P = 84.39 + 84.39 + 133.57 + 133.57

P =435.923 m

So, to the nearest meter

P ≈ 436m

The perimeter of the track is 436m

5 0
3 years ago
Y = -3x - 2 and 5x + 2y = 15
denis-greek [22]

Answer:

(-19, 55)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = -3x - 2

5x + 2y = 15

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                     5x + 2(-3x - 2) = 15
  2. Distribute 2:                          5x - 6x - 4 = 15
  3. Combine like terms:            -x - 4 = 15
  4. Isolate <em>x</em> term:                      -x = 19
  5. Isolate <em>x</em>:                               x = -19

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                    y = -3x - 2
  2. Substitute in <em>x</em>:                                     y = -3(-19) - 2
  3. Multiply:                                                y = 57 - 2
  4. Subtract:                                               y = 55
8 0
3 years ago
16/9 is equal to 2 times which fraction?
xxTIMURxx [149]

Answer:

The answer is 8/9

Hope this helps

6 0
3 years ago
Read 2 more answers
What’s the value of 5%
Firdavs [7]

Answer:

0.05 in decimal form

Step-by-step explanation:

I don't know if you accidentally left something out but if you did I can edit my answer or put the answer in the comments.

4 0
2 years ago
two opposite angles are congruent, necessary or not, and sufficient or not for a quadrilateral to be a parallelogram
hjlf

Answer: Ok here we go

Step-by-step explanation: Consecutive Angles

[insert drawing of irregular quadrilateral BEAR]

If you were to go around this shape in a clockwise direction starting at ∠B, you would next get to ∠E. Those two angles are consecutive. So are all these pairs:

∠E and ∠A

∠A and ∠R

∠R and ∠B

Consecutive angles have endpoints of the same side of the polygon.

Supplementary Angles

Supplementary angles are two angles adding to 180°. In a parallelogram, any two consecutive angles are supplementary, no matter which pair you pick.

Parallelograms

Parallelograms are special types of quadrilaterals with opposite sides parallel. Parallelograms have these identifying properties:

Congruent opposite sides

Congruent opposite angles

Supplementary consecutive angles

If the quadrilateral has one right angle, then it has four right angles

Bisecting diagonals

Each diagonal separates the parallelogram into two congruent triangles

Parallelograms get their names from having two pairs of parallel opposite sides.

Another interesting, and useful, feature of parallelograms tells us that any angle of the parallelogram is supplementary to the consecutive angles on either side of it.

We can use these features and properties to establish six ways of proving a quadrilateral is a parallelogram.

Proving A Quadrilateral is a Parallelogram

Can you be certain? Only by mathematically proving that the shape has the identifying properties of a parallelogram can you be sure. You can prove this with either a two-column proof or a paragraph proof.

Six Ways

Here are the six ways to prove a quadrilateral is a parallelogram:

Prove that opposite sides are congruent

Prove that opposite angles are congruent

Prove that opposite sides are parallel

Prove that consecutive angles are supplementary (adding to 180°)

Prove that an angle is supplementary to both its consecutive angles

Prove that the quadrilateral's diagonals bisect each other

Two-Column Proof

We can use one of these ways in a two-column proof. Bear in mind that, to challenge you, most problems involving parallelograms and proofs will not give you all the information about the presented shape. Here, for example, you are given a quadrilateral and told that its opposite sides are congruent.

Statement Reason:

GO ≅ TA and TG ≅ OA (Given)

Construct segment TO Construct a diagonal

TO ≅ TO Reflexive Property

△GOT ≅ △ TOA Side-Side-Side Postulate: If three sides of one △

are congruent to three sides of another △, then the two △ are congruent

∠GTO ≅ ∠ TOA CPCTC: Corresponding parts of congruent △ are

∠GOT ≅ ∠ OTA congruent

GO ∥ TA and TG ∥ OA Converse of the Alternate Interior Angles

Theorem: If a transversal cuts across two lines and the alternate interior angles are congruent, then the lines are parallel

▱ GOAT Definition of a parallelogram: A quadrilateral

with two pairs of opposite sides parallel

The two-column proof proved the quadrilateral is a parallelogram by proving opposite sides were parallel.

Paragraph Proof

You can also use the paragraph proof form for any of the six ways. Paragraph proofs are harder to write because you may skip a step or leave out an explanation for one of your statements. You may wish to work very slowly to avoid problems.

Always start by making a drawing so you know exactly what you are saying about the quadrilateral as you prove it is a parallelogram.

Here is a proof still using opposite sides parallel, but with a different set of given facts. You are given a quadrilateral with diagonals that are identified as bisecting each other.

[insert drawing of quadrilateral FISH with diagonals HI and FS, but make quadrilateral clearly NOT a parallelogram; show congruency marks on the two diagonals showing they are bisected]

Given a quadrilateral FISH with bisecting diagonals FS and HI, we can also say that the angles created by the intersecting diagonals are congruent. They are congruent because they are vertical angles (opposite angles sharing a vertex point).

Notice that we have two sides and an angle of both triangles inside the quadrilateral. So, we can use the Side-Angle-Side Congruence Theorem to declare the two triangles congruent.

Corresponding parts of congruent triangles are congruent (CPCTC), so ∠IFS and ∠ HSF are congruent. Those two angles are alternate interior angles, and if they are congruent, then sides FI and SH are parallel.

You can repeat the steps to prove FH and IS parallel, which means two pairs of opposite sides are parallel. Thus, you have a parallelogram.

In both proofs, you may say that you already were given a fact that is one of the properties of parallelograms. That is true with both proofs, but in neither case was the given information mathematically proven. You began with the given and worked through the problem, but if your proof "fell apart," then the given may have been wrong.

Since neither our two-column proof or paragraph proof "fell apart," we know the givens were true, and we know the quadrilaterals are parallelograms.

5 0
3 years ago
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