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horsena [70]
3 years ago
14

Quadrilateral JKLM has vertices J(–7, –2), K(–2, –2), L(–3, –4), and M(–6, –4). Find the midpoints of each of the sides JM andKL

.
Mathematics
2 answers:
wel3 years ago
8 0
To find the midpoint of a segment (or the midpoint between two points - here the endpoints of the side) we use the midpoint formula. What it comes down to is finding the "average" of the x-coordinate and the "average" of the y-coordinate.

The formula is as follows. The midpoint of the segment with endpoints (x_{1} ,y_{1}) and (x_{2} ,y_{2}) is given by ( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Let us find the midpoint of side JM. It does not matter which point we designate with the 1s and which we designate with the 2s so let's let J (-7,2) = (x_{1} ,y_{1}) and M (-6,-4) = (x_{2} ,y_{2}).

Now we plug these into the formula as follows: ( \frac{-7+-6}{2},\frac{-2+-4}{2}) = ( \frac{-13}{2},\frac{-6}{2})=(-6.5,-3)

Let us now find the midpoint of side KL. It does not matter which point we designate with the 1s and which we designate with the 2s so let's let K (-2,-2) = (x_{1} ,y_{1}) and L (-3,-4) = (x_{2} ,y_{2})

Now we plug these into the formula as follows: ( \frac{-2+-3}{2},\frac{-2+-4}{2}) = ( \frac{-5}{2},\frac{-6}{2})=(-2.5,-3)


Rudiy273 years ago
3 0
We calculate the midpoint by taking the average of the x- and y-coordinates of both points. For side JM, with point J(-7, -2) and point M(-6, -4), we average the x-coordinates to get (-7 - 6) / 2= -13/2, and the y-coordinates average to (-2 - 4) / 2 = -3. So the midpoint of side JM is (-13/2, -3).
The calculation is similar for side KL: (-2 - 3) / 2 = -5/2, and (-2 - 4) / 2 = -3, so the midpoint of side KL is (-5/2, -3).
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3 years ago
What is the value of 4x to the third +4x if x is 4
weqwewe [10]
The correct answer of
4{x}^{2}  + 4x
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4( {4}^{3} ) + 4(4)
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5 0
3 years ago
The vertex of an isosceles triangle measures 15 degrees more than one of its base angles how many degrees are there in a base an
Alexxandr [17]
V=B+15
V+2B=180
Therefore:
3B+15=180
B=55
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Check:
V+2B=180
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5 0
3 years ago
Neeeeed helpppppp please
MissTica

Answer:

Scale factor = 7

Step-by-step explanation:

Dilation with scale factor to map HEFG to DABC will be,

Scale factor = \frac{\text{Dimension of Image DABC}}{\text{Dimension of preimage HEFG}}

                    = \frac{\text{Length of CD}}{\text{Length of GH}}

Length of CD = Distance between two points C(0, -7) and D(-7, 0)

                       = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

                       = \sqrt{(-7-0)^2+(0+7)^2}

                       = \sqrt{98}

                       = 7\sqrt{2}

Length of GH = Distance between G(0, -1) and H(-1, 0)

                       = \sqrt{(-1-0)^2+(0+1)^2}

                       = \sqrt{2}

Scale factor = \frac{7\sqrt{2} }{\sqrt{2} }

                    = 7

6 0
3 years ago
Marci bought 4 yards of ribbon for $6 how much should marci expect to pay for 10 yards of the ribbon?
Vinvika [58]
Ok, let's find how much does 1 yard of ribbon cost. Let's divide!

6 / 4 = 1.5

Each yard costs $1.50, so let's multiply that by 101.5 * 10 = 15

Marci will pay $15 for 10 yards of the ribbon.
5 0
3 years ago
Read 2 more answers
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