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Rudiy27
3 years ago
13

Which is a factor of x2 + 5x – 247 (x-6) (x+6) (X-8) (X + 8)

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
7 0
There must be a typo in the equation. It must be x^2 + 5x - 24.
The factored equations is (x+8)(x-3).
The answer is (x+8).
:)
Travka [436]3 years ago
5 0

Answer:

the factor for x^2 + 5x - 24 is

(x + 8)

Step-by-step explanation:

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The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
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Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

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(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

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Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
Two gift shops sell postcards. Each gift shop charges a fixed amount per postcard. The prices, in cents, for different numbers o
Snowcat [4.5K]

1st gift shop:

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2nd gift shop:

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to get the system equation in getting the mass of each variable, you should subtract the two equation to simplified the formula.

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 - 21p + 14t = 51
-------------------------
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<span>50.962 is answer m8t</span>
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