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2 years ago

6

What is the probability that the first spinner will land on B, the second spinner will land on 3, and the third spinner will lan

d on Green?
1/24
1/12
1/8
1/4

1 answer:

Gemiola [76]2 years ago

7 0

1 50-50
2 1/4
3 1/3 this is all about fractions

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Jackson has 180 pieces of gum. He wants to share the pieces equally with his friends. Which table shows the relationship between

mars1129 [50]

Answer:

Step-by-step explanation:

6 0

2 years ago

Distance between two ships At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (naut

frozen [14]

Answer:

a) $\sqrt{144-288t+208t^2}$ b.) -12knots, 8 knots c) No e) $4\sqrt{13}$

Step-by-step explanation:

We know that the initial distance between ships A and B was 12 nautical miles. Ship A moves at 12 knots(nautical miles per hour) south. Ship B moves at 8 knots east.

a)

We know that at time t , the ship A has moved $12\dot t (n.m)$ and ship B has moved $8\dot t (n.m)$ . We also know that the ship A moves closer to the line of the movement of B and that ship B moves further on its line.

Using Pythagorean theorem, we can write the distance s as:

$\sqrt{(12-12\dot t)^2 + (8\dot t)^2}\\s=\sqrt{144-288t+144t^2+64t^2}\\s=\sqrt{144-288t+208t^2}$

b)

We want to find $\frac{ds}{dt}$ for t=0 and t=1

$\sqrt{144-288t+208t^2}|\frac{d}{dt}\\\\\frac{ds}{dt}=\frac{1}{2\sqrt{144-288t+208t^2}}\dot (-288+416t)\\\\\frac{ds}{dt}=\frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\\frac{ds}{dt}(0)=\frac{208\dot 0-144}{\sqrt{144-288\dot 0 + 209\dot 0^2}}=-12knots\\\\\frac{ds}{dt}(1)=\frac{208\dot 1-144}{\sqrt{144-288\dot 1 + 209\dot 1^2}}=8knots$

c)

We know that the visibility was 5n.m. We want to see whether the distance s was under 5 miles at any point.

Ships have seen each other = $s\leq 5\\\\\sqrt{144-288t+208t^2}\leq 5\\\\144-288t+208t^2\leq 25\\\\199-288t+208t^2\leq 0$

Since function $f(x)=199-288x+208x^2$ is quadratic, concave up and has no real roots, we know that $199-288x+208x^2>0$ for every t. So, the ships haven't seen each other.

d)

Attachedis the graph of s(red) and ds/dt(blue). We can see that our results from parts b and c were correct.

e)

Function ds/dt has a horizontal asympote in the first quadrant if

$\lim_{t \to \infty} \frac{ds}{dt}$

So, lets check this limit:

$\lim_{t \to \infty} \frac{ds}{dt}=\lim_{t \to \infty} \frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\=\lim_{t \to \infty} \frac{208-\frac{144}{t}}{\sqrt{\frac{144}{t^2}-\frac{288}{t}+208}}\\\\=\frac{208-0}{\sqrt{0-0+208}}\\\\=\frac{208}{\sqrt{208}}\\\\=4\sqrt{13}$

Notice that:

$4\sqrt{13}=\sqrt{12^2+5^2}$ =√(speed of ship A² + speed of ship B²)

5 0

3 years ago

I need help ASAP please!! Giving brainliest!!!

Lemur [1.5K]

It’s the third option

4 0

3 years ago

Find the inverse of square root f(n) = n – 3.

pogonyaev

Answer:

$f'(n) = n + 3$

Step-by-step explanation:

Given

$f(n) = n - 3$

Required

The inverse

$f(n) = n - 3$

Replace f(n) with y

$y = n - 3$

Swap positions of y and n

$n = y - 3$

Make y the subject

$y = n + 3$

Replace y with f'(n)

$f'(n) = n + 3$

4 0

3 years ago

Find the perimeter of the rectangle whose vertices are the points with coordinates (-1,-9), (4-9),(-1, -3), and (4, -3).

Airida [17]

Answer:

The perimeter is 22

Step-by-step explanation:

Using a graph would be the easiest way to solve this type of problem (just count the units from each point and add them all up). Perimeter= 2l+2w

If graph paper is not available then you may need to use your head a little bit and imagine a graph. You want to first find the length (or width because either can be it) by finding the two points with similar x or y values.

One of the lengths can be found by using (-1,-9) and (4,-9) because they have similar y values. Next you want to find the distance between the two values so that you can find the length. When two points are in different quadrants (use the image for reference) you would add the x values by their absolute values in meaning the distance the number is from 0 or that you change the negative numbers into positive numbers. Add 1 and 4 and you get 5. The length is 5 which you then multiply by 2 and get the length of both sides.

Because you have the two lengths the width where both of the x values are similar and find the distance between the points. You can use the two points (-1,-9) and (-1,-3). Use the absolute value of the two y values and subtract them because they are in the same quadrant (refer to the image if needed). Use the largest absolute value and subtract the lowest absolute value so that you get 9-3 which would give you 6. The width is 6 and you then multiply it by 2 so that you get 12. 12 is the width of both sides of the rectangle. Add all 4 sides together to get a perimeter of 22.

5 0

3 years ago