Answer:
im answer this for points pls dont mind
Answer:
-3+(-5)
Checking our answer:
Adding this does indeed give -8
Answer:
![\{\sqrt b, -\sqrt b\}](https://tex.z-dn.net/?f=%5C%7B%5Csqrt%20b%2C%20-%5Csqrt%20b%5C%7D)
Step-by-step explanation:
Given
![a^2 - b = 0](https://tex.z-dn.net/?f=a%5E2%20-%20b%20%3D%200)
Required
Determine the solution
Since b is a perfect square, the equation can be expressed as:
![a^2 - (\sqrt b)^2 = 0](https://tex.z-dn.net/?f=a%5E2%20-%20%28%5Csqrt%20b%29%5E2%20%3D%200)
Apply difference of two squares:
![(a - \sqrt b)(a + \sqrt b) = 0](https://tex.z-dn.net/?f=%28a%20-%20%5Csqrt%20b%29%28a%20%2B%20%5Csqrt%20b%29%20%3D%200)
Split:
![(a - \sqrt b)= 0 \ or\ (a + \sqrt b) = 0](https://tex.z-dn.net/?f=%28a%20-%20%5Csqrt%20b%29%3D%200%20%5C%20or%5C%20%28a%20%2B%20%5Csqrt%20b%29%20%3D%200)
Remove brackets:
![a - \sqrt b= 0 \ or\ a + \sqrt b = 0](https://tex.z-dn.net/?f=a%20-%20%5Csqrt%20b%3D%200%20%5C%20or%5C%20a%20%2B%20%5Csqrt%20b%20%3D%200)
Make a the subject in both equations
![a =\sqrt b \ or\ a =-\sqrt b](https://tex.z-dn.net/?f=a%20%3D%5Csqrt%20b%20%5C%20or%5C%20a%20%20%3D-%5Csqrt%20b)
The solution can be represented as:
![\{\sqrt b, -\sqrt b\}](https://tex.z-dn.net/?f=%5C%7B%5Csqrt%20b%2C%20-%5Csqrt%20b%5C%7D)
Step-by-step explanation:
Slope-intercept form: y = mx + c
y = x + 3 is already in this form.
3x + 3y = -9,
3y = -3x - 9
y = -x - 3.