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pav-90 [236]
3 years ago
5

What is the x-value of the solution to the system of equations?5x + 4y = 82x - 3y = 17​

Mathematics
1 answer:
katrin [286]3 years ago
7 0

Answer:

  x = 4

Step-by-step explanation:

You can eliminate the y-variables by adding 4 times the second equation to 3 times the first:

  3(5x +4y) +4(2x -3y) = 3(8) +4(17)

  15x +12y +8x -12y = 24 +68 . . . . eliminate parentheses

  23x = 92 . . . . . . . . . collect terms

  x = 92/23 = 4 . . . . . divide by 23

The x-value of the solution is 4.

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A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The
Readme [11.4K]

Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

3 0
3 years ago
What is the area of a circle if the radius is 13
Kisachek [45]
A = pi * r^2.....r = radius and pi = 3.14

A = (3.14)(13^2)
A = 3.14(169)
A = 530.66

7 0
3 years ago
Josh and Greg leave from the same place
nasty-shy [4]

9514 1404 393

Answer:

  • Josh: 32 mph, 64 mi
  • Greg: 64 mph, 320 mi

Step-by-step explanation:

Let x represent Josh's rate of travel in miles per hour. After 2 hours, his distance is ...

  distance = speed · time

  distance = x · 2 = 2x

Then 2x is Greg's rate of travel After 5 hours, his distance is ...

  distance = speed · time

  distance = (2x) · 5 = 10x

The distance they are apart is ...

  10x -2x = 256

  8x = 256

  x = 32

__

Josh's rate: 32 miles per hour; Josh's distance = (2 h)(32 mi/h) = 64 miles.

Greg's rate: (32 mi/h)·2 = 64 mi/h; Greg's distance = (5 h)(64 mi/h) = 320 miles.

<em>__</em>

<em>Check</em>: 320 miles - 64 miles = 256 miles . . . . correct separation

6 0
3 years ago
Please help me do number 5
Blizzard [7]
Make more sense ou of this question and I can help you out more ok?
7 0
3 years ago
Consider firing a pumpkin from a canon at a target that is 17 meters away. The pumpkin follows a quadratic path as displayed to
bixtya [17]
A.
(0,00
(2.6,7.9)
(4.8,12.4)
(9.7,15.1)

b.
well, the points don't look like they are on the line but they actually are (plot twist)


so
since (0,0) is on th egarph

0=a(0)²+b(0)+c
0=c
so
f(x)=ax²+bx+0 or
f(x)=ax²+bx

find a and b
sub points

(2.6,7.9)
7.9=a(2.6)²+b(2.6)
7.9=6.76a+2.6b

(4.8,12.4)
12.4=a(4.8)²+b(4.8)
12.4=23.04a+4.8b

use those 2 equations
7.9=6.76a+2.6b
12.4=23.04a+4.8b

eliminate b
multiply first equation by -4.8 and 2nd by 2.6 and add them
-37.92=-32.448a-12.48b
32.24=59.904a-12.48b +
-5.68=27.456a+0b

-5.68=27.456a
divide both sides by 27.456
(-5.68/27.456)=a
find b

12.4=23.04a+4.8b
12.4=(-130.8672/27.456)+4.8b
12.4+(130.8672/27.456)=4.8b
(12.4+(130.8672/27.456))/4.8=b

da equation is
y= \frac{-5.68}{27.456} x^2+ \frac{12.4+\frac{130.8672}{27.456}}{4.8}x



c. the roots are found with your calculator
the roots are at x=0 and x=17.287323943662
so very close to the target but not exactly on it
if the target has a radius of 0.287323943662 or more then it will hit the target
5 0
3 years ago
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