(c + b + a) + (-2a - 3b + c)
2 answers:
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Given:
Image of the ellipse
To find:
The equation of the image
Solution:
The given image is a ellipse.
Center of the ellipse = (0, 0)
x-axis points are (-3, 0) and (3, 0).
y-axis points are (2, 0) and (-2, 0).
Standard form of equation of ellipse:
where (h, k) is the center = (0,0)
a is the point on x-axis where y = 0. Hence a = 3.
b is the point on y-axis where x = 0. Hence b = 2.
Substitute this in the standard form of ellipse.
To make the denominator same multiply 1st term by and 2nd term by
.
Multiply by 36 on both sides
The equation of the image is .
<u>Given</u>:
Two parallel lines are cut by a transversal and form a pair of alternate interior angles.
One angle measures (6x + 5)° and the other measure (7x - 4)°
We need to determine the measure of each angle.
<u>Value of x:</u>
Since, the two angles are alternate interior angles, then the two angles are congruent.
Thus, we have;
Thus, the value of x is 9.
<u>Measure of each angle:</u>
The measure of each angle can be determined by substituting in the measures of each angle.
Thus, we have;
Thus, the measure of each angle is 59°