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2 years ago

A frog jumps across a pond. Its height, as a function of time, is modeled by y

Mathematics

1 answer:

sdas [7]2 years ago

6 0

Answer:The function is nonlinear

Step-by-step explanation:

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What is an equation of the line, in point-slope form, that passes through the given point and has the given slope? Point: (7,3)

Ymorist [56]

I think the answer to your question may be C.)

8 0

3 years ago

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

3 years ago

How many tissues does a carrot contain? Explain your reasoning.

zepelin [54]

Answer:

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6 0

3 years ago

Answer plz thanks !!!!!

svp [43]

Answer:

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Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The question says “The image shows the front of Bob’s barn.Bob plans on painting the front of his barn,not including the doors o

AleksandrR [38]

Bob need to paint 205 square feet.

Solution:

Length of the door = 7 ft

Breadth of the door = 5 ft

Area of the door = length × breadth

= 7 × 5

= 35

Area of the door = 35 ft²

The given image is a trapezoid.

Top base = 12 ft

Bottom base = 20 ft

Area of the trapezoid = $\frac{1}{2} \times\text{sum of the parallel sides}\times\text{height}$

$$=\frac{1}{2}\times(12+20)}\times15$

$$=\frac{1}{2}\times 32\times15$

= 240

Area of the trapezoid = 240 ft²

Surface area to paint = Area of the trapezoid – Area of the door

= 240 ft² – 35 ft²

= 205 ft²

Hence Bob need to paint 205 square feet.

6 0

3 years ago