The answer would be 10 11/20 or 10.55 in decimal form
Answer: range= 26, variance= 80 and standard deviation= 8.94
Step-by-step explanation:
Range = highest - lowest
Range = 146 - 120
Range= 26
Let m be mean
M=mean=sum/n
Mean=(120+134+146+127+138+133) / 6
M=798/6
M=133
The standard deviation sample formula:
S.D = sqrt( Summation of |x-m|^2 / n-1)
Let start finding:
|x-m|^2
For 1st: |120-133|^2=169
For 2nd: |134-133|^2=1
For 3rd: |146-133|^2=169
For 4th: |127-133|^2=36
For 5th: |138-133|^2=25
For 6th: |133-133|^2=0
Summation of |x-m|^2 = 400
The standard deviation formula is :
S.D = sqrt( Summation of |x-m|^2 / n-1)
S.D= sqrt(400 / 5)
S.D=sqrt(80)
S.D= 8.94
Variance = (Summation of |x-m|^2 / n-1)
Variance= 400/5
Variance= 80
Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Answer:
The rate of change is
ft^(2)/min
Step-by-step explanation:
The area of a circle is given by the following equation:

To solve this question, we have to realize the implicit differentiation in function of t. We have two variables, A and r. So

We have that:
.
We want to find 
So


Since the area is in square feet, the rate of change is in ft^(2)/min.
So the rate of change is
ft^(2)/min
Answer:
625
Step-by-step explanation: