Can someone please help meee!???

What percent of the time was the red line bus late?

Dmitriy789 [7]

8% I am sorry if I am wrong

8 0

3 years ago

A study was designed to investigate the effects of two variables, (1) A student's level of mathematical anxiety and (2) teach

Mashcka [7]

Answer:

$P(X>400)=P(\frac{X-\mu}{\sigma}>\frac{400-\mu}{\sigma})=P(Z>\frac{400-440}{20})=P(z>-2)$

And we can find this probability using the complement rule:

$P(z>-2)=1-P(z$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(z>-2)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(440,20)$

Where $\mu=440$ and $\sigma=20$

We are interested on this probability

$P(X>440)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>400)=P(\frac{X-\mu}{\sigma}>\frac{400-\mu}{\sigma})=P(Z>\frac{400-440}{20})=P(z>-2)$

And we can find this probability using the complement rule:

$P(z>-2)=1-P(z$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(z>-2)=1-P(z$

6 0

3 years ago

There are slips of paper that are numbered from 1 to 15 in a hat. What is the theoretical probability that a slip of paper that

lesya [120]

Okay! Let's write out all the numbers:

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

Now, let's bold (or you can circle them... or do really anything to them as long as they are standing out to you) the even numbers (remember all even numbers are divisible by 2)

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

Now let's list all the ones we highlighted:

2

4

6

8

10

12

14

Count up how many numbers that is.

You should get 7.

So, our answer is 7 out of 15 numbers.

Or as a fraction:

7/15 is our answer.

Note: A probability is the number of chances something has to happen out of the total number of chances. So in this case the number of even numbers out of the total number of numbers. You can apply this to any probability problem. Hope this helps!

Read more on Brainly.com - brainly.com/question/2150566#readmore

5 0

3 years ago

Read 2 more answers

Se necesitan conductores voluntarios para llevar a 80 estudiantes al juego de béisbol de campeonato. Los conductores tienen auto

NemiM [27]

Esta pregunta esta incompleta

Pregunta completa

Se necesitan conductores voluntarios para llevar a 80 estudiantes al juego de béisbol del campeonato. Los conductores cuentan con automóviles, con capacidad para 4 estudiantes, o camionetas, con capacidad para 6 estudiantes. La ecuación describe la relación entre la cantidad de automóviles y la cantidad de camiones que pueden transportar exactamente 80 estudiantes.

Seleccione todas las afirmaciones que sean verdaderas sobre la situación.

a) Si van 12 coches, se necesitan 2 furgonetas.

b) c = 14 y v = 4 son un par de soluciones de la ecuación.

c) Si van 6 coches y van 11 furgonetas, habrá espacio adicional.

d) 10 coches y 8 furgonetas no son suficientes para transportar a todos los estudiantes.

e) Si pasan 20 autos, no se necesitan camionetas.

f) 8 furgonetas y 8 coches son números que cumplen con las limitaciones en esta situación.

Answer:

La opción b, e y f.

Step-by-step explanation:

Pasando por las opciones dadas:

c = coches que pueden llevar a 4 estudiantes

v = furgonetas con capacidad para 6 estudiantes

a) Si van 12 coches, se necesitan 2 furgonetas.

= 12 (4) + 2 (6)

= 48 + 12

= 60

60 ≠ 80

La opción a es incorrecta

b) c = 14 y v = 4 son un par de soluciones de la ecuación.

14 (4) + 4 (6)

56 + 24 = 80 estudiantes

La opción b es correcta

c) Si van 6 coches y van 11 furgonetas, habrá espacio adicional.

Por lo tanto:

5 (4) + 11 (6)

= 20 + 66

= 86.

86 es mayor que 80, la opción c es correcta, habría un espacio adicional para 6 estudiantes.

d) 10 coches y 8 furgonetas no son suficientes para transportar a todos los estudiantes.

Por lo tanto:

10 (4) + 8 (6)

40 + 48

= 88

e) Si pasan 20 autos, no se necesitan camionetas.

20 (4) = 80 estudiantes

La opción e es correcta

f) 8 furgonetas y 8 coches son números que cumplen con las limitaciones en esta situación.

8 (6) + 8 (4)

= 48 + 32

= 80 estudiantes.

La opción b es correcta

Por lo tanto, la ecuacióna que describe la relación entre la cantidad de automóviles y la cantidad de camiones que pueden transportar exactamente 80 estudiantes es la opción b, e y f.

7 0

2 years ago

You flipped a coin 50 times and got 23 heads.What is the experimental probability of getting a head? Write your answer as a frac

lys-0071 [83]

Answer:

23/50, 0.46, and 46%

Step-by-step explanation:

This problem is stating that every fifty times you flip a coin you get 23 heads. Finding the fraction is simple, it would be 23/50 because it is expressing the probability. The problem clearly states that every 50 times you get 23 heads. To find the decimal, take the fraction, 23/50, and multiply the numerator and denominator by 2. you get 46/100 which is 0.46. A percent is just a fraction out of a 100 which would make the percent 46.

8 0

3 years ago