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Nataly_w [17]
3 years ago
14

Multiple choice geometry question!

Mathematics
1 answer:
suter [353]3 years ago
7 0

Answer: D m8

Step-by-step explanation:

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a. In order for ΔABC to be similar to ΔDEF, what must be true about the angles? Be specific. b. If you know that ΔABC is similar
igomit [66]
I) if the triangles are similar then the corresponding angles are congruent. this means that the angles are of the same size.

ii)  If ΔABC is similar to ΔDEF, therefore; m∠A = m∠D, m∠B=m∠E, and m∠C=m∠F,
thus, if m∠A= 52, m∠D=52, and if m∠E=65, then m∠B=65, thus to get m∠C; 
180- (52+65)
=  63 , therefore; m∠C= 63

iii) if two figures are similar they have the same shape and not necessarily the same size while if two figures are congruent then they have the same shape and size
5 0
3 years ago
What is the value of StartFraction 1 Over 6 Superscript 0 EndFraction? One-sixth 0 1 undefined
Allisa [31]

Answer:

1

Step-by-step explanation:

just took the test :)

8 0
3 years ago
Read 2 more answers
What is the approximate value for the modal daily sales?
Aleksandr [31]

Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

<em>13. What is the approximate value for the modal daily sales? </em>

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>

Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

Me= 3,100+400[\frac{125-116}{56} ]= 3164.29

<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

5 0
3 years ago
Please help me asap​
icang [17]
A, B, B,C for 8,9,10,11
7 0
3 years ago
Read 2 more answers
A baby weighed 7.25 pounds at birth. At the end of 8 months, the baby weighed 212
Vinil7 [7]

Answer:

1537pounds

Step-by-step explanation:

Given parameters:

  Weight of baby at birth  = 7.25 pounds

   

Unknown:

Weight at the end of 8months = ?

Solution:

 From the second sentence;

    Weight at the end of the eighth month = 212 x weight at birth.

Input the parameters and solve;

  Weight at the end of eighth month = 212 x  7.25  = 1537pounds

7 0
3 years ago
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