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Tema [17]
4 years ago
14

There is my question

Mathematics
1 answer:
Stells [14]4 years ago
3 0
4=c
5= a
I hope this helps you
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By which rule are these triangles congruent
zimovet [89]

Answer:

B:ASA ( by Angle Side Angel )

6 0
3 years ago
Tenemos 2 triangulos donde sus angulos mieden 46 y 66 respectivamente, y el lado adyacente a ellos mide 15cm, el criterio de con
HACTEHA [7]

Answer:

Puesto que se conocen dos ángulos seguidos y un lado adyacente tanto en uno como en otro triángulo, se debe emplear el criterio Ángulo-Lado-Ángulo (ALA) para determinar que los triángulos citados en el enunciado son congruentes.

Step-by-step explanation:

Puesto que se conocen dos ángulos seguidos y un lado adyacente tanto en uno como en otro triángulo, se debe emplear el criterio Ángulo-Lado-Ángulo (ALA) para determinar que los triángulos citados en el enunciado son congruentes.

5 0
3 years ago
What is the length of BC? If the answer is not an integer, leave it in simplest radical form. The diagram is not drawn to scale.
Snezhnost [94]

Answer:

13sqrt(2)

Step-by-step explanation:

Using pythagoras theorem

5 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
yKpoI14uk [10]

Answer:

Confidence Interval in 95% confidence level for the quality rating is (6.06,7.46)

Step-by-step explanation:

Confidence Interval can be calculated using the formula M±ME where

  • M is the mean of the sample
  • ME is the margin of error in a given confidence level

Using the sample obtained from 50 business travelers we get

  • Mean of the sample is 6.76
  • standard deviation of the sample is 2.526

Margin of error (ME) around the mean using the formula

ME=\frac{z*s}{\sqrt{N} } where

  • z is the corresponding statistic in 95% confidence level (1.96)
  • s is the standard deviation of the sample (2.526)
  • N is the sample size (50)

Using the numbers in the formula we get:

ME=\frac{1.96*2.526}{\sqrt{50} } ≈ 0.70

Then the confidence interval becomes 6.76±0.70

6 0
3 years ago
What is the solution of x^2+x-6/x-7<0 PLEASE HELP ME :( (it’s not the 2nd one i already tried it)
blsea [12.9K]

Answer:

the first one  \:x\le \:-3\quad \mathrm{or}\quad \:2\le \:x

Step-by-step explanation:

Factor x^2+x-6 :

Break the expression into groups

\left(x^2-2x\right)+\left(3x-6\right)

\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-2x\mathrm{:\quad}

x\left(x-2\right)

\mathrm{Factor\:out\:}3\mathrm{\:from\:}3x-6\mathrm{:\quad}

3\left(x-2\right)

x\left(x-2\right)+3\left(x-2\right)

\mathrm{Factor\:out\:common\:term\:}x-2

\left(x-2\right)\left(x+3\right)

\frac{\left(x-2\right)\left(x+3\right)}{x-7}\\

\frac{\left(x-2\right)\left(x+3\right)}{x-7}\le \:0

\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\frac{\left(x-2\right)\left(x+3\right)}{x-7}

\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:\le \:\:0

x

Merge Overlapping Intervals

x\le \:-3\quad \mathrm{or}\quad \:2\le \:x

6 0
3 years ago
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