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4 years ago

14

There is my question

1 answer:

Stells [14]4 years ago

3 0

4=c
5= a
I hope this helps you

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By which rule are these triangles congruent

zimovet [89]

Answer:

B:ASA ( by Angle Side Angel )

6 0

3 years ago

Tenemos 2 triangulos donde sus angulos mieden 46 y 66 respectivamente, y el lado adyacente a ellos mide 15cm, el criterio de con

HACTEHA [7]

Answer:

Puesto que se conocen dos ángulos seguidos y un lado adyacente tanto en uno como en otro triángulo, se debe emplear el criterio Ángulo-Lado-Ángulo (ALA) para determinar que los triángulos citados en el enunciado son congruentes.

Step-by-step explanation:

Puesto que se conocen dos ángulos seguidos y un lado adyacente tanto en uno como en otro triángulo, se debe emplear el criterio Ángulo-Lado-Ángulo (ALA) para determinar que los triángulos citados en el enunciado son congruentes.

5 0

3 years ago

What is the length of BC? If the answer is not an integer, leave it in simplest radical form. The diagram is not drawn to scale.

Snezhnost [94]

Answer:

13sqrt(2)

Step-by-step explanation:

Using pythagoras theorem

5 0

3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

yKpoI14uk [10]

Answer:

Confidence Interval in 95% confidence level for the quality rating is (6.06,7.46)

Step-by-step explanation:

Confidence Interval can be calculated using the formula M±ME where

M is the mean of the sample
ME is the margin of error in a given confidence level

Using the sample obtained from 50 business travelers we get

Mean of the sample is 6.76
standard deviation of the sample is 2.526

Margin of error (ME) around the mean using the formula

ME= $\frac{z*s}{\sqrt{N} }$ where

z is the corresponding statistic in 95% confidence level (1.96)

s is the standard deviation of the sample (2.526)

N is the sample size (50)

Using the numbers in the formula we get:

ME= $\frac{1.96*2.526}{\sqrt{50} }$ ≈ 0.70

Then the confidence interval becomes 6.76±0.70

6 0

3 years ago

What is the solution of x^2+x-6/x-7<0 PLEASE HELP ME :( (it’s not the 2nd one i already tried it)

blsea [12.9K]

Answer:

the first one $\:x\le \:-3\quad \mathrm{or}\quad \:2\le \:x$

Step-by-step explanation:

Factor $x^2+x-6$ :

Break the expression into groups

$\left(x^2-2x\right)+\left(3x-6\right)$

$\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-2x\mathrm{:\quad}$

$x\left(x-2\right)$

$\mathrm{Factor\:out\:}3\mathrm{\:from\:}3x-6\mathrm{:\quad}$

$3\left(x-2\right)$

$x\left(x-2\right)+3\left(x-2\right)$

$\mathrm{Factor\:out\:common\:term\:}x-2$

$\left(x-2\right)\left(x+3\right)$

$\frac{\left(x-2\right)\left(x+3\right)}{x-7}\\$

$\frac{\left(x-2\right)\left(x+3\right)}{x-7}\le \:0$

$\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\frac{\left(x-2\right)\left(x+3\right)}{x-7}$

$\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:\le \:\:0$

$x$

Merge Overlapping Intervals

$x\le \:-3\quad \mathrm{or}\quad \:2\le \:x$

6 0

3 years ago