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3 years ago

If the population of a town grew 21% up to 15,049. What is the population last year?

1 answer:

5 0

You can try formulating an equation to model this change:

Let 'x' be the population of the town last year. It follows that:
$1.21x = 15049 
$
and hence
$x = \frac{15049}{1.21}$

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Determine whether the figure is a parallelogram.

Nesterboy [21]

Answer:

The figure is a parralellogram

Step-by-step explanation:

it has 4 sides and one set is parallel

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3 years ago

What is 765903 rounded to the nearest thousand

Dominik [7]

765,000 should be the correct answer

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4 years ago

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Colin surveyed 12 teachers at school to determine how much each person budgets for lunch. He records his results in the table. W

zmey [24]

Answer:

As mean and median are equal, so the data will be in normal distribution in shape of a symmetrical "bell curve".

Step-by-step explanation:

The given data: 10 5 8 10 12 6 8 10 15 6 12 18

Mean is the simple average of all data. As, there are total 12 data, so the Mean will be: $\frac{10+5+8+10+12+6+8+10+15+6+12+18}{12}= \frac{120}{12}=10$

For finding the Median, first we need to rearrange the data according to the numerical order and then identify the middle value. So........

5 6 6 8 8 10 10 10 12 12 15 18

Here the middle values are 10 and 10. So, the median will be the average of those two middle values.

Thus, Median $=\frac{10+10}{2}=\frac{20}{2}=10$

We can see that, the relationship between the mean and the median is "they are equal". So, the data will be in normal distribution and the shape will be symmetrical "bell curve".

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3 years ago

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Liter of water i drink 1/4 before lunch and 2/3 of the rest after lunch how much do I bring in-between

tresset_1 [31]

Answer:

We have (2/3)x(1-1/4) - 1/4 = (2/3)x(3/4) -1/4 = 6/12 = 1/4 = 1/2 -1/4 = 2/4 - 1/4 = 1/4 do I bring in between;

Step-by-step explanation:

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3 years ago

Please help ASAP IM IN DESPREATE NEED OF HELP

Advocard [28]

Answer:

See the attached image for the graph of the first system.

Step-by-step explanation:

Here's how to graph the first system.

Start with the inequality $-y \le -2x-3$ . You can make this easier to work with by multiplying through by -1. Remember to switch the inequality sign when multiplying by a negative number. OK, you get the inequality

$y \ge 2x+3$ .

The graph will be a half-plane -- all the points on one side of a line. The line that is the boundary of the half-plane has an equation: $y=2x+3$ -- just use an = sign instead of the inequality sign.

Graph the line.

The equation of the line is in slope-intercept form: y = mx + b, so you can tell the y-intercept is 3 and the slope is 2 (think of it as a fraction 2/1). Graph the line by going to the point (0, 3) -- the y-intercept -- then use the slope 2/1 interpreted as "rise over run" to go up 2 units and right 1 unit, arriving at the point (1, 5). Draw the line through those points, (0, 3) and (1, 5).

Now you have to decide which side of the line the inequality $y \ge 2x+3$ is describing. To do this, pick a point which is not on the line, plug its coordinates into the inequality; if the result is true, shade the side of the line the point you picked is on (if false, shade the other side!)

An easy point to pick in this case is the origin, (0, 0). Put zeros in for x and y in the inequality, and you'll get the statement $0 \ge 2(0)+3 \, \Rightarrow \, 0 \ge 3$ . That's false, so shade the side of the line not containing the origin. In the image below, the shading is in purple.

All right, now for the other inequality, $x+2\le 0$ . Subtract 2 from both sides and the inequality becomes $x \le -2$ . This, too, graphs as a half-plane whose boundary line has equation $x=-2$ . Graph the line. A line with an equation that has x in it but not y is a vertical line with all its x-coordinates equal to the number on the right side of the equation. This line is vertical and goes through points such as (-2, 0).

Pick a point not on the line (the origin works again). Put the coordinates into the inequality to get $0\le -2$ which is false. Shade the side of the vertical line which does not contain the origin. In the image below, the shading is in black.

Finally, YAY! \o/ , the solutions to the system are all the points in the plane that got shaded twice. In the image, they are the cross-hatched points above the purple line and to left of the black line.

Note: If you get a system with three inequalities, you'll be graphing three half-planes and looking for points that got shaded three times!

Note: One of your questions has the inequalities $x \ge 0$ and $y \ge 0$ in it. These two inequalities say that the x and y coordinates are both positive or zero, confining your attention to Quadrant I in the upper-right part of a graph, above the x-axis and to the right of the y-axis.

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3 years ago