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deff fn [24]
3 years ago
9

What's the 5th sequence of 9

Mathematics
1 answer:
Yuki888 [10]3 years ago
5 0
The sequence of 9 is 9, 81, 729, 6561, 59049, 531441, ect. hope this helps
                                 1   2      3       4         5          6   
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How do I fine x to the nearest tenth ??
Ipatiy [6.2K]

Answer:

x = 13.6

Step-by-step explanation:

Here, we want to find the value of x

to find the value of x. we are going to use the sine rule

It states that the ratio of the sine of an angle to the measure of the side facing the angle is fixed for a triangle

In this case;

11/ sin 27 = x/ sin 34

x = 11 sin 34/sin 27

x = 13.6

4 0
3 years ago
The ratio of two numbers is 3 is to 7 if the smaller is 18 find the greater number ​
777dan777 [17]

21 id the greater   number

Hope you understand

4 0
3 years ago
Question 15 options:
Sergio039 [100]

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the line y = - x

a point (x, y ) → (- y, - x )

Thus

F(- 4, - 1 ) → F'(1, 4 )

G(- 10, 4 ) → G'(- 4, 10 )

5 0
3 years ago
Somebody please help me with this geometry work
dimulka [17.4K]

Answer:

m∠EGF = 65°  and m∠CGF = 115°

Step-by-step explanation:

Given;

∠EFG = 50°

EF = FG

Solution,

In ΔEFG m∠EFG = 50° and EF = FG.

Since triangle is an isosceles triangle hence their base angles are always equal.

∴m\angle FEG = m\angle EGF

Let the measure of ∠EGF  be x.

∴ m\angle FEG = m\angle EGF = x

Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."

m∠EFG + m∠FEG + ∠EGF = 180

50\°+x+x=180\°\\50\°+2x=180\°\\2x= 180\°-50\°\\2x=130\°\\x=\frac{130}{2}= 65\°

Hence

m∠EGF = 65°  

Also 'The sum of angles that are formed on a straight line is equal to 180°."

m∠EGF + m∠CGF = 180°

65° + m∠CGF = 180°

m∠CGF = 180° - 65° = 115°

Hence m∠EGF = 65°  m∠CGF = 115°

8 0
3 years ago
Solving for x thank youu
Svetach [21]

Answer:

sqrt (90)

Step-by-step explanation:

(13+5)  is to z    as  z is to 5

(13+5) / z = z/5

18/z = z/5

90 = z^2

z = sqrt (90)

5 0
2 years ago
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