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igomit [66]
3 years ago
10

Find the midpoint of the line segment with the endpoints A and B. A(4.8): B(10,2)

Mathematics
1 answer:
rjkz [21]3 years ago
6 0

Answer:

The midpoint is ( 7,5)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinate of the endpoints and divide by 2

( 4+10)/2 = 14/2 = 7

To find the y coordinate of the midpoint, add the y coordinate of the endpoints and divide by 2

(8+2)/2 = 10/2 = 5

The midpoint is ( 7,5)

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Solve for b.<br> r = (b-5)m
alukav5142 [94]

Answer:

b=5m+r/m

Step-by-step explanation:

Let's solve for b.

r=(b−5)(m)

Step 1: Flip the equation.

bm−5m=r

Step 2: Add 5m to both sides.

bm−5m+5m=r+5m

bm=5m+r

Step 3: Divide both sides by m.

bm/m=5m+r/m

b=5m+r/m

Answer:

b=5m+r/m

6 0
3 years ago
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hank wants to divide 345 pieces of construction paper evenly among his 23 classmates. how many pieces will be left over
Bogdan [553]
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3 years ago
Identify the digit with the given place value in number 173.514 hundredths
Llana [10]

Answer: We are given the number 173.514

Each of the digits in this number has the following place value:

\begin{gathered} 1\rightarrow\text{ Hundreds} \\ 7\rightarrow\text{ Tens} \\ 3\rightarrow\text{ Ones} \\ \text{.}\rightarrow\text{  Decimal Point} \\ 5\rightarrow\text{ Tenth} \\ 1\rightarrow\text{  Hundreth} \\ 4\rightarrow\text{  Thousandth} \end{gathered}

Secondly, We have to identify the numbers in digit 185.712

\begin{gathered} 1\rightarrow\text{ Thousand} \\ 8\rightarrow\text{ Hundred} \\ 5\rightarrow\text{ Tens} \\ \text{. Decimal point} \\ 7\text{ }\rightarrow\text{Thenth} \\ 1\rightarrow\text{ Hundreth} \\ 2\text{ }\rightarrow\text{ Thousandth} \\  \end{gathered}

5 0
1 year ago
Stacy hits the jackpot one day at the gumball machine. She puts in a quarter and gets 444 gumballs rather than 111. The radius o
inn [45]

Answer: 3617.28 cubic millimeters.

Step-by-step explanation: I used the formula of a sphere since a gumball is a shape of a sphere and plugged the radius into the formula.

I got that the volume of a single gumball is 288π cubic millimeters.

Since there are 4 gumballs, i multiplied the volume by 4.

The total volume of the four gumballs add up to be 1152π .

Lastly, I multiplied 1152 by pi

and got the answer to be 3617.28 cubic millimeters

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4 years ago
The data shows the survey results of 75 randomly selected students.
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D

Step-by-step explanation:

The answer is d

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