Answer:
4
Step-by-step explanation:
x^2/ y^4
Let x=8 and y=2
8^2 / 2^4
PEMDAS says powers first
64 / 16
Divide next
4
Answer with Step-by-step explanation:
We are given that

Where t corresponds to the year 2000=0
a.
Substitute the values


b.In 2004
t=4


c.In 2013
t=13

X^2+10x+29=0
Quadratic Formula:
−b±√b^2−4(ac)/2a
Substitute the values :
a=1, b=−10, and c=29
into the quadratic formula and solve for
x.
10±√(−10)^2−4•(1•29)/ 2•1
Simplify.
Answer: x=5±2i
a. The water in the second tank decreases at a faster rate than the water in the first tank. The initial water level in the first tank is greater than the initial water level in the second tank.
Step-by-step explanation:
Step 1:
It is given that the time remaining in first tank is given by the equation y = -10x + 80. We can get the total water in the tank by substituting x = 0 in the equation. The total volume of water in first tank is 80 litres.
Step 2:
The value of y in the equation y = -10x + 80 will be 0 when the tank is fully empty. When y = 0 , 10x = 80, so x = 8. We can conclude that the first tank empties fully in 8 minutes.
In 8 minutes 80 litres of water is emptied from first tank. So the water in the first tank decreases at rate of 80 / 8 = 10 litres per minute
Step 3:
As per the given table for the second tank, 60 litres of water remains when x =0. So the total volume of water in the second tank = 60 litres.
Step 4:
As per the given table for the second tank, the volume becomes 0 in 5 minutes. In 5 minutes 60 litres of water is emptied from second tank. So the water in second tank decreases at rate of 60 / 5 = 12 litres per minute.
Step 5:
The initial volume of water in first tank is higher. The water in second tank decreases at a faster rate than the first tank.
Step 6:
The only correct option is:
a. The water in second tank decreases at a faster rate than the water in the first tank. The initial water level in first tank is greater than the initial water level in the second tank.
Answer:
4/15 = height of lamp/(15+5)
4/15 = height of lamp/20
20/15 = 1 5/15
1 5/15 times taller