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3 years ago

Find the value of x. Round the nearest tenth. The diagram is not drawn to scale.

Mathematics

1 answer:

svetoff [14.1K]3 years ago

3 0

Use your trig: SOH, CAH, TOA. Which one would you use? Label each of your sides. Plug in your angle in your trig: ie. Cos(24): 11/x.

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The product of two consecutive negative even integers is 24. What is the smaller of the two numbers?

Karo-lina-s [1.5K]

Answer:

The smaller one is -6, the bigger one is -4.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Please answer this correctly without making mistakes

victus00 [196]

Answer:

Question 2

Step-by-step explanation:

2) The time when she woke up was - 3° C

During nature walk, temperature got 3° C warmer than when she woke up.

So, temperature during nature walk = - 3 + 3 = 0° C

3 0

2 years ago

What is a / b (2x - 12) = c / d ; x ?

Alex17521 [72]

we are given

$\frac{a}{b} (2x-12)=\frac{c}{d}$

we can solve for x

We can isolate x

step-1: Multiply both sides by b/a

$\frac{b}{a}*\frac{a}{b} (2x-12)=\frac{b}{a}*\frac{c}{d}$

$(2x-12)=\frac{bc}{ad}$

step-2:Add 12 both sides

$(2x-12)+12=\frac{bc}{ad}+12$

$2x=\frac{bc}{ad}+12$

step-3: combine right side

$2x=\frac{bc+12ad}{ad}$

step-4:Divide both sides by 2

$x=\frac{bc+12ad}{2ad}$ ..............Answer

3 0

3 years ago

g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for <em>h: </em>

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0

3 years ago

Can someone please help me with this

Airida [17]

Answer:

The answer is yum yum fruit ! Work is shown below :)

6 0

3 years ago