Answer:
A) 5/6
B) -67/30 (or) -2 7/30
A) -9/2 (or) -4 1/2
Step-by-step explanation:
A) 2/3(5)-5/2=3 1/3-5/2 = 10/3-5/2 = 20/6-15/6= 5/6
B) 2/3(2/5)-5/2= 4/15-5/2 = 8/30-75/30 = -67/30
A) 2/3(-3)-5/2=-2-5/2= -4 1/2
Answer:
The constant force exerted on the ball by the wall is 119.68 N.
Step-by-step explanation:
Consider the provided information.
It is given that the mass of the ball is m = 2.2 kg
The initial velocity of the ball towards left is 7.4 m/s
So the momentum of the ball when it strikes is = 
The final velocity of the ball is -6.2 m/s
So the momentum of the ball when it strikes back is = 
Thus change in moment is: 
The duration of force exerted on the ball t = 0.25 s
Therefore, the constant force exerted on the ball by the wall is:

Hence, the constant force exerted on the ball by the wall is 119.68 N.
Answer:
b. circle; 
Step-by-step explanation:
The given conic has equation;

We complete the square to obtain;

This is a circle with center;

This implies that;

When the circle is rotated through an angle of
,
The new center is obtained using;
and 
We plug in the given angle with x and y values to get;
and 
This gives us;

The equation of the rotated circle is;

Expand;

Multiply through by 4; to get

Write in general form;

Divide through by 2.

Answer:
The IQR is a better measure of spread for dance competitions than for badminton games.
Step-by-step explanation:
I understand from "Dance Competition box plot has interquartile ranges approximately between 60 and 130" that quartile 1 is at 60 and quartile 3 is at 130, then, the interquartile range (IQR) is 130 - 60 = 70.
Similarly, from Badminton box plot, quartile 1 is at 90 and quartile 3 is at 150, then, the interquartile range is 150 - 90 = 60.
IQR is a measure of statistical dispersion, that is, as IQR increase, spread increase.