3 years ago

Divide 25 by 8 write the quotient with a fraction

Mathematics

1 answer:

ehidna [41]3 years ago

5 0

3 1/8 or 3.125 or 25/8

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4 years ago

1. (a) Show that 487 is prime. (b) Find the prime factorization of 2922. Show all working.

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2 years ago

If a,b,c,d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)(x+d)(x^2+ex+1), what is the value of a+b+c+d+e?

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Answer:

Step-by-step explanation:

Hello,

If $X=x^2$ it becomes

$X^3-289X^2-X+289=(X^2-1)(X-289)$

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$X^2-1=(X-1)(X+1)=(x^2-1)(x^2+1)=(x+1)(x-1)(x^2+1) \\\\x^2-289=x^2-17^2=(x-17)(x+17)$

So,

$x^6-289x^4-x^2+289=(x^2-1)(x^2+1)(x^2-289)=(x-1)(x+1)(x+17)(x-17)(x^2+1)$

a = 1

b = 1

c = 17

d = 17

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Thanks

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3 years ago

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mote1985 [20]

Sorry I'm not sure if I'm right just my thinking...

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