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tankabanditka [31]
3 years ago
9

What pH is needed to produce this value of Q if the concentration and pressure values are [Br2]=2.50×10?4M, [Br?]=11.85M, [SO42?

]=8.35M, and PSO2=2.50×10?5atm? Express your answer numerically to two decimal places. q=1.4x10^-26
Chemistry
1 answer:
Bingel [31]3 years ago
4 0

Explanation:

The given reaction will be as follows.

       2H_{2}O + Br_{2} + SO_{2} \rightarrow 2Br^{-} + SO^{2-}_{4} + 4H^{+}

Hence, expression that represents relation between given reaction and Q will be as follows.

              Q = \frac{[Br^{-}]^{2}[SO^{2-}_{4}][H^{+}]^{4}}{[Br_{2}]P_{SO_{4}}}

          1.4 \times 10^{-26} = \frac{(11.85)^{2} \times (8.35) \times [H^{+}]^{4}}{(2.5 \times 10^{4}) \times 2.50 \times 10^{5}}

                [H^{+}]^{4} = 7.46 \times 10^{-34}

                 [H^{+}]= 5.22 \times 10^{-10}

As relation between pH and [H^{+}] is as follows.

                     pH = -log [H^{+}]

                           = -log 5.22 \times 10^{-10}

                           = -(0.717 - 10)

                           = 9.28

Thus, we can conclude that the pH needed to produce the given value of Q is 9.28.

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Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . Suppose 48.1 g
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Answer:

69.7 g of Na₂SO₄

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

Next, we shall determine the masses of H₂SO₄ and NaOH that reacted and the mass of Na₂SO₄ produced from the balanced equation. This can be obtained as shown below:

Molar mass of H₂SO₄ = (2×1) + 32 + (4×16)

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Mass of H₂SO₄ from the balanced equation = 1 × 98 = 98 g

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Mass of NaOH from the balanced equation = 2 × 40 = 80 g

Molar mass of Na₂SO₄ = (2×23) + 32 + (4×16)

= 46 + 32 + 64

= 142 g/mol

Mass of Na₂SO₄ from the balanced equation = 1 × 142 = 142 g

SUMMARY:

From the balanced equation above,

98 g of H₂SO₄ reacted with 80 g of NaOH to produce 142 g of Na₂SO₄.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

98 g of H₂SO₄ reacted with 80 g of NaOH.

Therefore, 48.1 g of H₂SO₄ will react with = (48.1 × 80)/98 = 39.3 g of NaOH.

From the calculation made above, we can see that only 39.3 g of NaOH out of 51 g given was needed to react completely with 48.1 g of H₂SO₄. Therefore, H₂SO₄ is the limiting reactant and NaOH is the excess reactant.

Finally, we shall determine the maximum mass of Na₂SO₄ produced from the reaction. This can be obtained by using the limiting reactant as illustrated below:

NOTE: H₂SO₄ is the limiting

From the balanced equation above,

98 g of H₂SO₄ reacted to produce 142 g of Na₂SO₄.

Therefore, 48.1 g of H₂SO₄ will react to produce = (48.1 × 142)/98 = 69.7 g of Na₂SO₄.

Thus, 69.7 g of Na₂SO₄ were obtained from the reaction.

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