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Ivahew [28]
3 years ago
9

Ethan went to the grocery store and bought bottles of soda and bottles of juice. Each bottle of soda has 45 grams of sugar and e

ach bottle of juice has 35 grams of sugar. Ethan purchased a total of 19 bottles of juice and soda which collectively contain 755 grams of sugar. Determine the number of bottles of soda purchased and the number of bottles of juice purchased.
Mathematics
1 answer:
Anna35 [415]3 years ago
7 0

9 bottles of soda and 10 juice bottles are purchased

<em><u>Solution:</u></em>

Given that,

Sugar contained by each soda bottle = 45 grams

Sugar contained by each juice bottle = 35 grams

Let,

x be the number of soda bottles

y be the number of juice bottles

Given that,

<em><u>Ethan purchased a total of 19 bottles of juice</u></em>

Therefore, we get,

x + y = 19 ---------- eqn 1

<em><u>Ethan purchased a total of 19 bottles of juice and soda which collectively contain 755 grams of sugar</u></em>

<em><u>Therefore, we frame a equation as:</u></em>

45 \times x + 35 \times y = 755

45x + 35y = 755 --------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>From eqn 1,</u></em>

x = 19 - y --------- eqn 3

Substitute eqn 3 in eqn 2

45(19 - y) + 35y = 755

855 - 45y + 35y = 755

10y = 100

y = 10

<em><u>Substitute y = 10 in eqn 3</u></em>

x = 19 - 10

x = 9

Thus 9 bottles of soda and 10 juice bottles are purchased

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To solve this we are going to use the exponential function: f(t)=a(1(+/-)b)^t
where
f(t) is the final amount after t years
a is the initial amount
b is the decay  or grow rate rate in decimal form
t is the time in years

Expression A 
f(t)=624(0.95)^{4t}
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate b, we are going to use the formula: b=|1-base|*100%
b=|1-0.95|*100%
b=0.05*100%
b=5%
We can conclude that expression A decays at a rate of 5% every three months.

Now, to find the initial value of the function, we are going to evaluate the function at t=0
f(t)=624(0.95)^{4t}
f(0)=624(0.95)^{0t}
f(0)=624(0.95)^{0}
f(0)=624(1)
f(0)=624
We can conclude that the initial value of expression A is 624.

Expression B
f(t)=725(1.12)^{3t}
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
b=|1-base|*100%
b=|1-1.12|*100
b=|-0.12|*100%
b=0.12*100%
b=12%
We can conclude that expression B grows at a rate of 12% every 4 months.

Just like before, to find the initial value of the expression, we are going to evaluate it at t=0
f(t)=725(1.12)^{3t}
f(0)=725(1.12)^{0t}
f(0)=725(1.12)^{0}
f(0)=725(1)
f(0)=725
The initial value of expression B is 725.

We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months. 

- Expression A has an initial value of 624, while expression B has an initial value of 725.

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