Πr²h(2)-πr²h(1)=πr²(h(2)-h(1))=V2-V1
V2-V1=πr²(h(2)-h(1))
314-188.4=π*2²(h(2)-h(1))
(h(2)-h(1))=(314-188.4)/4π=10
difference is 10 cm
Answer:
did you understand ? do I have to solve all?
Answer:
BCD
Step-by-step explanation:
Answer:
Q1. (a) (i) p = -9, q = 11
Q3. (a) Line 1: x = 0.5
Line 2: x = -2
Q3. (b) (i) (ii) For both lines, they will be perpendicular to the x-axis and they will pass their respective x-coordinates of 1 and -2 1/2.
Step-by-step explanation:
Q1. (a) (i) 5(-5) - 3p = 2
-25 - 3p = 2
3p = -25 - 2
p = -27/3
p = -9
5(7) - 3q = 2
35 - 3q = 2
3q = 35 - 2
3q = 33
q = 11
Q3. (a) Since all points on Line 1 have x-coordinates of 0.5, we can conclude that the equation is x = 0.5. Same goes for Line 2, of which all points have x-coordinates of -2 instead, making the equation x = -2.
Hope this helped!
The shaded area is to the upper right of the line, so the equation needs to be addition the inequality sign needs to be greater than or equal to a positive value.
The correct answer would be C.