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allsm [11]
3 years ago
12

Y= 10x - 32 what is the x and y value of this equation

Mathematics
1 answer:
Marrrta [24]3 years ago
7 0

Answer:

y=10x-32 \\ \\ x=\frac{y}{10}+3.2

Step-by-step explanation:

y=10x-32

Because that's the equation given.

To solve for x, isolate the variable and then divide by the coefficient.

y=10x-32 \\ \\ 10x=y+32 \\ \\ x=\frac{y}{10}+\frac{32}{10} \\ \\ x=\frac{y}{10}+3.2

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AveGali [126]

Answer:

Hewo!

3.41 m - 341 cm

3.41 m - 0.00341 km

3.41 m - 3410 mm

hope it helps!

5 0
3 years ago
Which function is not linear?
Umnica [9.8K]

Answer: y=x^2+2

Step-by-step explanation:

y=x^2+2 (answer choice 3) is parabolic and not linear

that is the answer

8 0
3 years ago
Find the area of the triangle
Goshia [24]

I wrote the steps down, hopefully you understand them and the answer is on the lower right corner.

6 0
3 years ago
Question 4
Elanso [62]

Answer:

a A = 30 + 0.45 n

b A = 90.3

c 0 customers

Step-by-step explanation:

Given

Base\ Amount = 30

Rate = 0.45 per customer

Solving (a): Amount (A) on n customers

This is calculated as:

A = Base\ Amount + Rate * n

A = 30 + 0.45 * n

A = 30 + 0.45 n

Solving (b): Amount on 134 customers

In this case: n = 134

So:

A = 30 + 0.45 * 134

A = 30 + 60.3

A = 90.3

Solving (c): Customers at noon.

At noon, the amount is 30.

So:

A = 30 + 0.45 n

30 = 30 + 0.45n

Collect like terms

0.45n = 30 - 30

0.45n =0

n = 0

6 0
3 years ago
Drag and drop formal proof. Prove the Polygon Exterior Angle Sum Theorem for the enclosed triangle, that is ∠1+∠2+∠3=360°
jasenka [17]

Answer:

The sum of all the external angles of a triangle is 360°.

Step-by-step explanation:

Let there are n sides in a polygon.

So, there are n internal angles in the polygon, let ∠i1, ∠i2, ∠i3, ..., ∠in are the measure of n internal angles of the polygon.

The measure of external angle corresponding to ∠i1,  ∠1= 180°-∠i1,

The measure of external angle corresponding to ∠i2, ∠2 = 180°-∠i2,

Similarly, the measure of external angle corresponding to ∠in, ∠n = 180°-∠in.

Now, the sum of all the external angles of the polygon,

(∠1+∠2+...+∠n)=(180°-∠i1)+(180°-∠i2)+...+(180°-∠in)

=(180°+180°+...n times)-(∠i1+∠i2+...+∠in)

=n x 180° - (∠i1+∠i2+...+∠in)

As ∠i1+∠i2+...+∠in is the sum of all the internal angles of the polygon.

So, the sum of all the external angles of the polygon =

(n x 180°) - (sum of all the internal angles of the polygon).

In the case of a triangle, n=3  and the sum of all the three internal angles, ∠i1+∠i2+∠i3 = 180°.

Therefore, the sum of all the external angles of a triangle,

∠1+∠2+∠3 =3x180°-(∠i1+∠i2+∠i3)

                 =540°=180°

                 =360°.

Hence, the sum of all the external angles of a triangle is 360°.

5 0
3 years ago
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