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inysia [295]
3 years ago
12

HELP Simplify a^15/a^5 A) a^-3 B) a^-10 C) a^3 D) a^10

Mathematics
1 answer:
NemiM [27]3 years ago
6 0

the answer is in photo ma homie

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What is true about the completely simplified sum of the polynomials 3x squared y squared minus 2 x y to the power of 5 and negat
12345 [234]

Answer:

The sum is a binomial with a degree of 6.

Step-by-step explanation:

To find : What is true about the completely simplified sum of the polynomials 3x^2y^2-2xy^5 and -3x^2y^2+3x^4y ?

Solution :

The polynomials  3x^2y^2-2xy^5 and -3x^2y^2+3x^4y ,

The sum of polynomial is given by,

S=3x^2y^2-2xy^5+(-3x^2y^2+3x^4y)

On simplifying , we get,

S=3x^2y^2-2xy^5-3x^2y^2+3x^4y

S=-2xy^5+3x^4y

Therefore, the result obtained is a binomial with a degree of 6.

4 0
3 years ago
a school had 690 students sign up for the trivia teams if they wanted to have nine teams with the same number of students on eac
uysha [10]

Answer:

3 more students need to sign up

Step-by-step explanation:

Let the equal number of students in 9 teams be x.

Total number of signed up students = 690.

Let t be the required number of students to be signed.

Therefore, 9x = 690+t.

This means, 690+t is a multiple of 9.

The least value of t to make 690+t, a multiple of 9 is 3 and hence,

\frac{693}{9}

= 77

Hence, 3 more students need to sign up and each of the 9 teams consists of 77 students.

5 0
2 years ago
Round your answer to the nearest hundredth BC=?
miskamm [114]

Answer:

BC = 1.71

Step-by-step explanation:

well to start we have to know the relationship between angles, legs and the hypotenuse  in a right triangle

α = 70°

a: adjacent  = BC

h: hypotenuse = 5

sin α = o/h

cos α= a/h

tan α = o/a

we see that it has (angle, adjacent, hypotenuse)

we look at which meets those data between the sine, cosine and tangent

is the cosine

cos α = a/h

Now we replace the values ​​and solve

cos 70 = a/5

0.34202 = a/5

0.34202 * 5 = a

1.7101 = a

round to the neares hundredth

a = 1.7101 = 1.71

BC = 1.71

7 0
2 years ago
There are 340 freshman at BHSS. This is one hundred less than two times the number of sophomores. Find the number of sophomores
natta225 [31]
To put it into an equation, it would be:

340 = 2x - 100

with x being the amount of sophomores at BHSS.

Solve it:

340 + 100 = 2x

2x = 440

x = 220

The number of sophomores at BHSS is 220.




5 0
3 years ago
Shipping department 17 employees budget of 3715 budget
Masja [62]
Please explain more...
5 0
3 years ago
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