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scoundrel [369]
2 years ago
13

Which statements can be concluded from the diagram and used to prove that the triangles are similar by the SAS similarity theore

m?
PLEASE HELP ME
!!!!!1

Mathematics
2 answers:
velikii [3]2 years ago
6 0

Answer:

RS/VU=ST/UT and ∠S≅∠U

Step-by-step explanation:

we know that

The <u>Side-Angle-Side Similarity Theorem </u>states that: If two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar

In this problem the included angle is

∠S≅∠U

therefore

side RS must be proportional to side VU  and side ST must be proportional to side UT

so

RS/VU=ST/UT

<em>Verify</em>

substitute the given values

12/6=16/8

2=2 -----> is true

therefore

The two sides are proportional

vfiekz [6]2 years ago
6 0

Find out  statements from the diagram that proves triangles are similar by the SAS similarity theorem ANSWERBy SAS similarity theoremIf the two right triangles contain corresponding sides through equal ratios, they are said to be similar take  In the Δ RST and ΔVUT  take Now take ∠RST = ∠ VUT = 90° ( shown in the diagram )therefore the triangle shown in diagram i.e Δ RST and ΔVUT are similar   by SAS similarity property.

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A study indicates that 62% of students have have a laptop. You randomly sample 8 students. Find the probability that between 4 a
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Answer:

72.69% probability that between 4 and 6 (including endpoints) have a laptop.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they have a laptop, or they do not. The probability of a student having a laptop is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A study indicates that 62% of students have have a laptop.

This means that n = 0.62

You randomly sample 8 students.

This means that n = 8

Find the probability that between 4 and 6 (including endpoints) have a laptop.

P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{8,4}.(0.62)^{4}.(0.38)^{4} = 0.2157

P(X = 5) = C_{8,5}.(0.62)^{5}.(0.38)^{3} = 0.2815

P(X = 6) = C_{8,6}.(0.62)^{6}.(0.38)^{2} = 0.2297

P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.2157 + 0.2815 + 0.2297 = 0.7269

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Step-by-step explanation:

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Answer:

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