Answer:
the answer is an equal sign
I think you divide.. find the mean of all of the numbers?
Answer:
The answer is 7.96×10⁷ .
Step-by-step explanation:
As the decimal moves to the <u>l</u><u>e</u><u>f</u><u>t</u> , you have to add one more power to the base 10 :
e.g
7 960 000.0 = 7 960 000×10¹
796 000.00 = 796 000×10²
79 600.000 = 79 600×10³
7 960.0000 = 7 960×10⁴
796.00000 = 796×10⁵
79.600000 = 79.6×10⁶
7.9600000 = 7.96×10⁷
* Take note :

0 < a < 10 ('a' must be greater than 0 but smaller than 10)
Review your notes and have a friend test you on them. Go over anything you had trouble on by reading it 10 times, writing it 10 times, and saying it out loud 2 times. It should help you remember and good luck! :)
Answer:
82.31% of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per microliter
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Approximately what percentage of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per microliter?
This is the pvalue of Z when X = 5.4 subtracted by the pvalue of Z when X = 4.2. So
X = 5.4



has a pvalue of 0.9842
X = 4.2



has a pvalue of 0.1611
0.9842 - 0.1611 = 0.8231
82.31% of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per microliter