<span>3sinx+4cosx=5
=> 3/5 sinx +4/5 cosx = 1
let cosA=3/5 => sinA=4/5
=> cosAsinx + sinAcosx = 1
=> sin(x+A) = 1
Now,
4sinx - 3cosx
= 5(4/5sinx - 3/5 cosx) [multipying numerator and denominator by 5]
= 5(sinAsinx - cosAcosx)
= -5{cos(x+A)} = -5[root{1-(sin(x+A)^2)}] = -5 x 0 = 0 Ans 0
TRICK: if asinx+bcosx is given then multiply numerator and denominator by root(a^2 +b^2)
this method is useful in many questions </span>
Answer is •D because of the seburation
The Answer Of How Many Muffins And Cupcakes Are Left Is 121
First find average
(5+5+5+5+7+9)/6=6
now see how much they each are differnt
5 to 6 is 1
5 to 6 is 1
5 to 6 is 1
5 to 6 is 1
7 to 6 is 1
9 to 6 is 3
average those
(1+1+1+1+1+3)/6=8/6=4/3=1.333
answer is 1.33
1st answer: 7j = 91
2nd answer: 13
First, write the statement as an equation.
7j= 91
Now, divide both sides of the equation by 7.
j = 13
