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Lana71 [14]
2 years ago
13

First question- Mean of: 95, 18, 51, 1, 22, 5

Mathematics
2 answers:
BlackZzzverrR [31]2 years ago
8 0
To find the mean, add up the numbers and divide the answer by the number of numbers you added up.

1) 95 + 18 + 51 + 1 + 22 + 5 = 192
    192 / 6 = 32
    The mean of the numbers is 32.

2) 67 + 103 + 94 + 65 + 18 + 114 + 94 + 63 + 94 + 27 = 739
    739 / 10 = 73.9
    The mean of the numbers is 73.9.

    To find the median, line up all the numbers from least to greatest. Then see          which number is in the middle. If there are two numbers in the middle, find            the mean of the two numbers.

    18, 27, 63, 65, 67, 94, 94, 94, 103, 114
    67 and 94 are in the middle. The mean of 67 and 94 is 80.5.
    The median is 80.5.
kati45 [8]2 years ago
7 0
The mean is 32
The median is 67
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3 years ago
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Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
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Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

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2 years ago
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dedylja [7]

Answer:

Step-by-step explanation:

This is function composition. We will take the g function and plug it into the f function wherever we see an x. That will look like this when it's done but before it's simplified:

f(g(x))=\frac{5x-4-3}{5x-4} and that can be simplified down to

f(g(x))=\frac{5x-7}{5x-4}

The domain of this function will be all real numbers EXCEPT for the one(s) that cause the denominator to become undefined. Set the denominator equal to 0 and solve for x:

5x - 4 = 0 so

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In other words, D = {x | x ≠ 4/5}

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Answer:

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