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pav-90 [236]
3 years ago
7

Wendy throws a dart at this square-shaped target: Part A: Is the probability of hitting the black circle inside the target close

r to 0 or 1? Explain your answer. Part B: Is the probability of hitting the white portion of the target closer to 0 or 1? Explain your answer.

Mathematics
2 answers:
netineya [11]3 years ago
8 0

Answer:

A: 0, B: 1

Step-by-step explanation:

You don't really have to do any calculations for this question if you know that a probability that is closer to 0 is very unlikely whereas a probability that is closer to 1 is very likely. From the picture, because there is a lot more white area than black, it would be unlikely to hit the black and likely to hit the white, we know that the probability of hitting the black circle is closer to 0 and the probability of hitting the white portion is closer to 1.

Irina-Kira [14]3 years ago
3 0

Using the formula for area of a circle, pi*r^2, we can determine that the area of the circle is 3.14159 [units] squared. Meanwhile, the area of the white area can be determined by finding the total area and subtracting the area of the circle. This gives us a total white space of about 96.85841.

Ratio of black to white space: 3:97 (rounded to whole numbers)

Ratio of white to black space: 97:3 (rounded to whole numbers)

This may seem incorrect but that is simply because the image is not drawn to scale.

The thrower has a 3% chance of hitting black and a 97% chance of hitting white. I assume the question makes the assumption that the landing spot is random and that the dart will always hit the target, so with this information we get the following answers.

Part A: Closer to 0

Part B: Closer to 1

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Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
4 years ago
Percy solved the equation x2 + 7x + 12 = 12. His work is shown below. Is Percy correct? Explain.
antoniya [11.8K]
= > x² + 7x + 12 = 12

= > x² + ( 4 + 3 )x + 12 = 12

= > x² + 4x + 3x + 12 = 12

= > x( x + 4 ) + 3( x + 4 ) = 12

= > ( x + 4 ) ( x + 3 ) = 12


Percy did correct till this step. But by doing like this, Percy can't get the values of the variable x.



Percy should follow the following steps :

= > x² + 7x + 12 = 12


Add -12 on both sides,


= > x² + 7x + 12 - 12 = 12 - 12

= > x² + 7x = 0

= > x( x + 7 ) = 0

= > ( x = 0 ) or ( x + 7 = 0 )

= > ( x = 0 ) or ( x = - 7 )



Hence, required value(s) of x is 0 or -7
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8 0
4 years ago
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adoni [48]
B is the correct one
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(Absolute value of 12 - 20) - (27/3 + 11) ^2
rodikova [14]

Answer:

the answer is 400-8=394.

Step-by-step explanation:

6 0
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Use the quadratic formula to find both solutions to the quadratic equation given below 3x^2-x+6=0
Mrac [35]

Hello from MrBillDoesMath!

Answer:

Choice E and F

Discussion:

From the quadratic formula with a = 3, b = -1, and c = 6

x =  ( -b +\- sqrt(b^2 - 4ac)  ) / (2a)       => substitute in a,b,c from above

x = ( -(-1) +\- sqrt((-1)^2 - 4(3)(6)) / (2*3)  => discriminant = 1 - 72 = -71)

x = ( 1 +\- sqrt(-71))/ 6

which are choices E and F

Thank you,

MrB

6 0
4 years ago
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