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valina [46]
3 years ago
5

A town has a population of 2000 and grows 4% every year. What will be the population after 15 years?

Mathematics
1 answer:
Serjik [45]3 years ago
7 0

Answer:

the answer is 3200

Step-by-step explanation:

2000*4%= 80

80*15=1200

2000+1200=3200

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Assume that the number of messages input to a communication channel in an Exponential distribution with 7 messages arriving in a
NARA [144]

The probability that more than 3 messages will arrive during a 30-second interval is P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}.

According to the statement

we have given that the an Exponential distribution with 7 messages arriving in a 10 second period and we have to find the probability that more than 3 messages will arrive during a 30-second interval.

So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

And the given information is that :

3 messages will arrive during a 30-second interval.

Then

Probability = P(X=1) + P(X=2) + P(X=3).Then

The probability become according to the exponential distribution:

P(X=1)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\\P(X=2)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\\P(X=3)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\

And then substitute the values in it then

Probability = \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\ +\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\ + \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\

This is the probability.

So, The probability that more than 3 messages will arrive during a 30-second interval is P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}.

Learn more about probability here

brainly.com/question/24756209

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2 years ago
Convert 52.68 feet per hour to inches per minute using dimensional analysis
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3 0
3 years ago
N = 32 ÷ (5 - 1)<br> N = 32 ÷ ?<br> N =?
Roman55 [17]

Answer

N = 32 ÷ (5 - 1)

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Step-by-step explanation:

4 0
3 years ago
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