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Juliette [100K]
3 years ago
11

The average of 20 numbers is 0. among them at least how many of them can be greater than 0.

Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

The correct option is A.

Step-by-step explanation:

The correct option is A.

According to the given statement:

Average of 20 numbers= 0.

So we have avg = sum/20.

That implies sum = 0.

Hence at the most, there can be 19 positive numbers.  

(Such that if the sum of these 19 positive numbers is x, 20th number will be -x)....

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K/x=w+v, solve for x
makkiz [27]

Answer:

im pretty sure the answer is (k-w)/v = x

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3 years ago
Find the y-intercept of a line parallel to 8x – 2y = 12 and passes through the point (5, 3).
Dmitry_Shevchenko [17]

Answer:

-17

Step-by-step explanation:

8x -2y= 12

<em>Divide</em><em> </em><em>the</em><em> </em><em>whole</em><em> </em><em>equation</em><em> </em><em>by</em><em> </em><em>2</em><em>:</em>

4x -y= 6

<em>Rewrite the equation into the slope-intercept form (y=mx+c, where m is the gradient while c is the y-intercept).</em>

-y= -4x +6

y= 4x -6

Thus, gradient of given line= 4.

Since parallel lines have the same gradient, gradient of line= 4.

y= 4x +c

<em>To find the y-intercept of the lone, substitute a pair of coordinates.</em>

When x=5, y=3,

3= 4(5) +c

3= 20 +c

c= 3 -20

c= -17

Thus, the y-intercept of the line is -17.

7 0
2 years ago
Which Heinz Ketchup offer is the better deal? (Assume the price stays proportional and the Ketchup is
Andrew [12]
B because you get more for a cheaper price.
7 0
2 years ago
What additional information do you need to prove that ∆AMD ≅ ∆CNB by the HL Theorem?
Maurinko [17]
(H)ypotenuse (L)eg, right-triangle theorem.

based on the provided graph, we know the hypotenuses are equal, thus the tickmarks, so H is true, now the L part, we only need either of the pair of legs to be equal DM = NB or AM = CN, if either one is true, we're golden.
8 0
3 years ago
Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i
Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

(c) SD (X) = 2.73

Step-by-step explanation:

Let <em>X</em> = <em>r</em><em> </em>= a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = <em>p</em> = 0.35.

The sample selected is of size <em>n</em> = 12.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 12 and <em>p</em> = 0.35.

The probability function of a binomial random variable is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x}

(a)

For <em>X</em> = 0 the probability is:

P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006

For <em>X</em> = 1 the probability is:

P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037

For <em>X</em> = 2 the probability is:

P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

E(X)=np

The expected number of vehicles out of 12 that will tailgate is:

E(X)=np=12\times0.35=4.2

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

SD(X)=np(1-p)

The standard deviation of vehicles out of 12 that will tailgate is:

SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

4 0
3 years ago
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