The average of 20 numbers is 0. among them at least how many of them can be greater than 0.

Mathematics

1 answer:

Neporo4naja [7]3 years ago

8 0

Answer:

The correct option is A.

Step-by-step explanation:

The correct option is A.

According to the given statement:

Average of 20 numbers= 0.

So we have avg = sum/20.

That implies sum = 0.

Hence at the most, there can be 19 positive numbers.

(Such that if the sum of these 19 positive numbers is x, 20th number will be -x)....

You might be interested in

Which statement is true about the domain of y = 3(2^-x)? Explain.

SVEN [57.7K]

We want to determine the domain of ${y=3 \cdot 2^{-x}=3 \cdot ({2^{-1}})^x=3 \cdot ({ \frac{1}{2}})^x$

any function of the form $y=f(x)=a \cdot b^x$ is called an "exponential function",
the only condition is that b is positive and different from 1, and a is a nonzero real number.

The domain of such functions is all real numbers.

That is for any x, the expression 3(2^-x) "makes sense".

Answer: The domain is all real numbers

8 0

3 years ago

Identify sinJ as a fraction and as a decimal rounded to the nearest hundredth.

KiRa [710]

In the given right triangle, the trigonometric ratio, sin J has a fractional value of 5/13 and a decimal value of 0.39.

In trigonometry, for a right triangle, the sine (sin) of any angle θ is given as the ratio of its opposite side to the hypotenuse of the triangle, that is, sin θ = (opposite side)/(hypotenuse).

In the question, we are asked to find the trigonometric ratio, sin J, for the given right triangle JKL.

The side opposite to angle J is KL, which has a value of 3 units.

The hypotenuse of the given right triangle is JK, which has a value of 7.8 units.

Thus, sin J can be calculated as:

sin J = KL/JK = 3/7.8 = 5/13 = 0.39.

Thus, in the given right triangle, the trigonometric ratio, sin J has a fractional value of 5/13 and a decimal value of 0.39.

Learn more about trigonometric ratios at

brainly.com/question/20367642

#SPJ1

8 0

1 year ago

Please help ASAP!!!