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strojnjashka [21]
3 years ago
9

Please answer this correctly

Mathematics
1 answer:
NeTakaya3 years ago
5 0

Answer:

15 feet by 13 feet.

Step-by-step explanation:

Let the length be x and the width be y  feet.

Perimeter:

2x + 2y = 56

Area:

xy = 195

From the second equation x = 195/y

Substitute for x in the fist equation:

2 * (195/y) + 2y = 56

390/y + 2y = 56

Multiply through by y:

390 + 2y^2 = 56y

2y^2 - 56y + 390 = 0

y^2 - 28y + 195 = 0

y = 13 , 15

Now substitute for y = 13 in  equation 1:

2x + 26 = 56

2x = 30

x = 15..

X is the length  so the length = 15 and the width = 13 feet.

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The complete question in the attached figure

Part A) How much sand is currently in the container?
[sand  currently in the container]=(5)*(4 1/2)*(2.25)-----> (5)*(4.5)*(2.25)
[sand  currently in the container]=50.625 in³

the answer Part a) is 50.625 in³

Part B) How much more sand could the container hold before?
[sand could the container hold before]=[5*4.5*3]-[50.625]
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the answer Part B) is 16.875 in³

Part C) What percent of the container is filled with sand?
the volume of container is [5*4.5*3]=67.5 in³
the volume filled with sand=50.625 in³
therefore
if 100%----------------> 67.5 in³
 X---------------------> 50.625 in³
X=(50.625*100)/67.5=75 %

the answer Part C) is 75%





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