Answer:
Read explanation and apply it
Step-by-step explanation:
The vertex form of a quadratic equation is 
The general form of a quadratic equation is 
The factored form of a quadratic equation is 
The one which reveals the zeros of f(x) without needing to alter the equation is the factored form
.
When f(x)=0, we have 
The values of x are
and
.
I hope this guides you to choose the correct answer.
Answer:
86%
Step-by-step explanation:
A percentage is a number or a ratio expressed as a fraction over 100. For example, 50% in fraction form is known as 50/100. 45% is known as 45/100.
Lets say the fraction was 43/50. We already know that a percentage is a number expressed as a fraction over 100, in order to convert this fraction into a percentage, we would have to multiply the denominator by a certain number in order to make it 100.
43/50 = x/100
If we multiply 50 × 2 = 100, so now we have to do the same for the numerator, and also multiply it by 2.
43 × 2 = 86
50 × 2 = 100
Now we know that the fraction is 86/100, now in order to convert it into percantage form, it would just be 86%
<u>T</u><u>h</u><u>e</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u> </u><u>i</u><u>s</u><u> </u><u>8</u><u>6</u><u>%</u>
Answer:
68
Step-by-step explanation:
24+24=48
=68
10+10=20
2
Step-by-step explanation:
common ratio(r)=-3/4
a2÷a1=r
32/9÷-128/27=-3/4
therefore using the common ratio to find the fourth term is just by multiplying the third term -8/3 by the common ratio -3/4
which equals = 2
Answer:
use pythagoras theorem to solve ur problem.