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pishuonlain [190]
4 years ago
12

Solve,justify and check: 3(7+5n)=6n+6(1+4n)

Mathematics
2 answers:
jenyasd209 [6]4 years ago
6 0
The answer should be 1=n
vlabodo [156]4 years ago
4 0

Answer:

1=n

Step-by-step explanation:

Step 1- Distribute into the parenthesis.

7(3)+5(3)n= 6n+1(6)+4(6)n

Step 2- Multiply

21+15n= 6n+6+24n

Step 3- Add common variables to simplify.

21+15n= (24n+6n)+6

21+15n= 30n+6

Step 4- Subtract the smallest variable to both sides.

21+15n= 30n+6

   -15n  -15n

21= 15n+6

Step 5- Subtract 6 to both sides.

21= 15n+6

-6           -6

15= 15n

Step 6- Divide both sides by 15.

<u>15</u>= <u>15n</u>

15   15

1=n

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Step-by-step explanation:

g(x) is the graph of f(x) shifted up 4 units.

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2 years ago
What is the maximum r-value for the polar equation r = -3 + 5 sin theta? Note that a maximum r-value is a maximum value of (r),
kipiarov [429]

Answer:

+2

Step-by-step explanation:


The given equation, r = -3 + 5 sin theta, includes a sine term whose max value is +5 and whose min value is -5.  We are interested in finding the max value that r can have.  To obtain this, take that constant term, -3, and add teh max value of the sine function, which is +5.  Net:  5 - 3 = 2.

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3 years ago
Mike has 20 CD's. 20% are rock and 60% are Pop. How many are other Genres? Explain.
Ratling [72]
4 are rock and 12 are pop, so 4 CD's are other
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4 years ago
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Charlie reads quickly. He reads 1\dfrac371 7 3 ​ 1, start fraction, 3, divided by, 7, end fraction pages every \dfrac23 3 2 ​ st
OLEGan [10]
<h2>Answer:</h2>

The number of pages he will read in one minute is:

        2\dfrac{1}{7}\ \text{pages}

<h2>Step-by-step explanation:</h2>

It is given that:

Charlie reads 1\dfrac{3}{7}\ \text{pages} in every \dfrac{2}{3}\ \text{minutes}.

We know that:

1\dfrac{3}{7}=\dfrac{10}{7}

This means that:

Charlie reads \dfrac{10}{7}\ \text{pages} in every \dfrac{2}{3}\ \text{minutes}.

This means that:

\text{In}\ \dfrac{2}{3}\ \text{minutes he reads}\ \dfrac{10}{7}\ \text{pages}\\\\\text{Hence}

\text{In}\ 1\ \text{minute he will read}\ \dfrac{\dfrac{10}{7}}{\dfrac{2}{3}}\ \text{pages}

\text{In}\ 1\ \text{minute he will read}\ \dfrac{10\times 3}{7\times 2}\ \text{pages}

Hence,

\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}

Hence,

\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}

\text{In}\ 1\ \text{minute he will read}\ 2\dfrac{1}{7}\ \text{pages}

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3 years ago
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