Hello,
To exist x≠0
if x>0 then
x+2/x>=3==>x²+2>=3x
==>x²-3x+2>=0
==>(x-2)(x-1)>=0 positive out of the roots
==> (x<=1 or x>=2) and x>0
==>(0<x<=1) or (x>=2)
else
x<0
x+2/x>=3==>x²+2<=3x
==>x²-3x+2<=0 negative betheen the roots
==>(1<=x<=2) and x<0 : no solution
end if
Yup its 53 Degrees you got it right :)
Answer:
A. 1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
-5x - 1 ≤ -9
<u>Step 2: Solve for </u><em><u>x</u></em>
- Add 1 to both sides: -5x ≤ -8
- Divide -5 on both sides: x ≥ 8/5
Here we see that any value <em>x</em> greater than or equal to 1.6 would work as a solution.
Therefore, our answer is A. 1, as it doesn't work as a solution.
