All categories

3 years ago

31.447 to nearest tenth

2 answers:

4 0

The tenth place is the place value that is directly to the right of the decimal point.
31.447 rounded to the nearest tenth would be 31.4

never [62]3 years ago

3 0

31.4 will be your answer

You might be interested in

Here is the question: Jamey purchased a new boat for 61014.00. She read that the value of the new boats change by -2/19 in the f

olga55 [171]

The value of Jamey's boat after the first year of purchase is $54,591.47.

<h3>What is a reduction in value?</h3>

The change in the value of the new boat can be described as a reduction in value, which is akin to the depreciation of the initial value.

The reduction means that the value of the boat fell after the first year of use.

The reduction or change in value and the new value after the first year can be computed as follows:

<h3>Data and Calculations:</h3>

Purchase price = $61,014

Change in value after first year = -2/19

Change in value (dollars) = $6,422.53 ($61,014 x 2/19)

Value after the first year = $54,591.47 ($61,014 - $6,422.53)

Thus, the value of Jamey's boat after the first year of purchase is $54,591.47.

Learn more about reduction in the value of an asset at brainly.com/question/25806993

#SPJ1

6 0

2 years ago

Ethan and Chloe shared £50 in the ratio 1:4

Alexxx [7]

Answer:

10:40

Step-by-step explanation:

5 0

3 years ago

Please can someone help me with this question

sasho [114]

Answer:

r = - $\frac{6a}{1-5m^2}$

Step-by-step explanation:

Rewrite the equation as $\sqrt{x} 6a+r/5r$ = m

Remove the radical on the left side of the equation by squaring both sides of the equation.

( $\sqrt{\frac{6a+r}{5r} )^{2}$ = m^2

Then, you simplify each of the equation.

Rewrite: ( $\sqrt{\frac{6a+r}{5r} )^{2}$ as $\frac{6a+r}{5r} = m^{2}$

Remove any parentheses if needed.

Solve for r.

Multiply each term by r and simplify."

Multiply both sides of the equation by 5.

6a+r= m^2r⋅(5)

Remove parentheses.

Move 5 to the left of (m ^2) r

6a+r=5m^2)r

Subtract 5m^2)r from both sides of the equation.

6a+r-5m^2)r=0

Subtract 6a from both sides of the equation.

r-5m^2)r=-6a

Factor r out of r-5m^2)r

r(1-5m^2)=-6a

Divide each term by 1-5m^2 and simplify.

r = - $\frac{6a}{1-5m^2}$

There you go, hope this helps!

4 0

3 years ago

Last question of my homework pls <3

dimaraw [331]

Answer:

J(2, 5 )

Step-by-step explanation:

Using the section formula

$x_{J}$ = $\frac{1(-2)+2(4)}{2+1}$ = $\frac{-2+8}{3}$ = $\frac{6}{3}$ = 2

$y_{J}$ = $\frac{1(1)+2(7)}{2+1}$ = $\frac{1+14}{3}$ = $\frac{15}{3}$ = 5

Thus J = (2, 5 )

7 0

3 years ago

9. Determine how long it takes for 80% of the material to decay.

Vilka [71]

Using an exponential function, it is found that it takes 18.6 days for 80% of the material to decay.

The amount of a substance after t days is modeled by:

$A(t) = A(0)e^{-kt}$

In which:

k is the decay rate, as a decimal.

A(0) is the initial amount.

The half-life is of 8 days, hence $A(8) = 0.5A(0)$ , and this is used to find k.

$A(t) = A(0)e^{-kt}$

$0.5A(0) = A(0)e^{-8k}$

$e^{-8k} = 0.5$

$\ln{e^{-8k}} = \ln{0.5}$

$-8k = \ln{0.5}$

$k = -\frac{\ln{0.5}}{8}$

$k = 0.08664339757$

Hence:

$A(t) = A(0)e^{-0.08664339757t}$

The time it takes for 80% of the material to decay it t for which $A(t) = 0.2A(0)$ , hence:

$0.2A(0) = A(0)e^{-0.08664339757t}$

$e^{-0.08664339757t} = 0.2$

$\ln{e^{-0.08664339757t}} = \ln{0.2}$

$-0.08664339757t = \ln{0.2}$

$t = -\frac{\ln{0.2}}{0.08664339757}$

$t = 18.6$

It takes 18.6 days for 80% of the material to decay.

To learn more about exponential functions, you can take a look at brainly.com/question/24906920

5 0

3 years ago