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Varvara68 [4.7K]
3 years ago
10

5x + 2y = 8

Mathematics
2 answers:
Mrrafil [7]3 years ago
8 0
Mult the 2nd by 2 then add. this eliminates one of the variables (y) and allows you to solve the other one x
vitfil [10]3 years ago
5 0

Answer:

So it's b.) right

You might be interested in
In circle o, the length of radius OL is 6 cm and the length
AlekseyPX

Answer:

14.2cm

Step-by-step explanation:

The diagram representing the circle and its attributes has been attached to this response.

<em>As shown in the diagram;</em>

The circle is centered at o,

The length of radius OL = 6cm

The length of the arc LM = 6.3cm

The angle MON = 75°

The angle LOM = θ

<em>Remember that;</em>

The length, L, of an arc is given by;

L = (θ / 360) x (2πr)         -------------(i)

Where;

θ is the angle subtended by the arc

r = radius of the circle.

Using the formula in equation (i), let's calculate the angle θ subtended by arc LM as follows;

L = (θ / 360) x (2πr)  

Where;

L = length of arc LM = 6.3cm

r = radius of the circle = length of radius OL = 6cm

<em>Substitute these values into the equation to get;</em>

6.3 = (θ / 360) x (2 x π x 6)

6.3 = (θ / 360) x (12 x π)

6.3 = (θ / 30) x (π)              [Take π = 22/7]

6.3 = (θ / 30) x (22 / 7)

θ = \frac{6.3*30*7}{22}

θ = 60.14°

Therefore, the angle subtended by arc LM is 60.14°

Now, from the diagram,

The angle subtended by arc LMN is;

θ + 75° = 60.14° + 75° =  135.14°

Let's now calculate the length of arc LMN using the same equation (i)

L = (θ / 360) x (2πr)  

Where;

L = length of arc LMN

θ = angle subtended by LMN = 135.14°

r = radius of the circle = length of radius OL = 6cm

<em>Substitute these values into the equation;</em>

L = (135.14° / 360°) x (2 x π x 6)             [Take π = 22/7]

L = 14.15cm

Therefore, the length of arc LMN is 14.2cm to the nearest tenth.

6 0
3 years ago
Help?? This question is gonna be similar to a test question tommorow i do not understand
tigry1 [53]
You should calculate( the area of a circle of radius 15 cm ) minus the area of the circle of radius (15 cm - width of the frame). I am not able to read the number, sorry. 
That is the surface area of the frame.

Then, if area of circle radius is 100%, the % of face of the clock is:

(100xareaCircle(15cm-widthframe))/areaCircle15cm


8 0
3 years ago
Can someone please help me with this asap ... Please and thank you
OLga [1]

Answer:

Step-by-step explanation:

From the question given in the picture,

a). Since, NR bisects a straight angle ∠MNP,

  ∠MNR ≅ ∠PNR

  m∠MNR + m∠PNR = 180°

  2(m∠MNR) = 180°

  m∠MNR = 90°

  Therefore, ∠MNR and ∠PNR are the right angles.

  Since, QN divides ∠MNR in two parts,

  Therefore, ∠QNR will be an acute angle (less than 90°).

  ∠MNR + ∠SNR = ∠MNS

  90° + ∠SNR = ∠MNS

  Therefore, m∠MNS will be more than 90°.

    ∠MNS will be an obtuse angle (greater than 90°).

(b). Since, NR divides ∠MNP and ∠QNS,

    ∠MNR ≅ ∠PNR

     ∠QNR ≅ ∠SNR

     ∠MNQ ≅ ∠PNS

(c). m∠MNR = 90°

     Since, NR bisects ∠QNS,

     ∠QNR ≅ ∠RNS

     m∠QNR = m∠RNS = 30°

     m∠QNR + m∠RNS = 30° + 30°

     m∠QNR + m∠RNS = 60°

     m∠QNS = 60° [Since, m∠QNS = m∠QNR + m∠RNS]

     m∠QNP = m∠QNS + m∠SNP

     m∠QNP = m∠QNS + (m∠PNR - m∠SNR)

     m∠QNP = 60° + (90° - 30°) = 120°        

4 0
3 years ago
In right triangle ABC, D is the midpoint of the hypotenuse AB. If AD=(5x + 1)cm and CD=(2x + 10)cm, find AB
guapka [62]
Can you confirm is hypotenuse should be AC...

ADB would make another right triangle if I am correct and you could use the pyth theorem to determine AB<span />
8 0
3 years ago
I'd greatly appreciate the help-
dem82 [27]

Answer:

The 3rd option

Step-by-step explanation:

To prove that 2 triangles are similar, we need to prove that 2 pairs of their angle measurements are congruent.

This is because all triangles have 180 degrees, so if 2 pairs are congruent, the remaining angles will also be congruent

We know that m<D=m<E

We also know that m<DCA=m<ECB because they are vertical angles.

Vertical angles are always congruent.

Therefore, the triangles are similar.

The correct similarity statement would be 1, since <D corresponds with <E.

Now let's look at the 3rd Statement. To prove that two lines are similar, we would have to prove that their alternate interior angles are congruent.

A pair of alternate interior angles would be <D and B or or <E  and <A

There is no way to prove this, since we do not know any of the angle  or that measurements or if the triangles are isosceles triangles.

Hence, the correct choice would be 1 only.

7 0
3 years ago
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