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zysi [14]
3 years ago
10

The mean number of people per day visiting a museum in July was 160. If 20 more people each day visited the museum in August, wh

at was the mean number of people per day visiting in August?
620
180
160
640
Mathematics
2 answers:
Valentin [98]3 years ago
7 0

Answer:

  180

Step-by-step explanation:

160 + 20 = 180

When the same value is added to each member of a set, the mean increases by that value.

PIT_PIT [208]3 years ago
5 0
Since the number of days in July and in August is the same, there is no need to work out on the total number per month.

The mean number of people per day in August = 160 + 20 = 180

Answer: 180
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The answer would be 31.4.
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3.) A linear function passes through the points (0, 2) and (-4,0).
kotegsom [21]

Answer:

Step-by-step explanation:

The x-intercept is where y is 0.

The y-intercept is where x is 0.

The x-intercept would be (-4, 0) and the y-intercept (0, 2)

Using the slope formula, (y2-y1/x2-x1), we can find the slope which is 1/2.

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Consider the equation below.
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Answer-6x+10=16

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Concerns about climate change and CO2 reduction have initiated the commercial production of blends of biodiesel (e.g., from rene
OverLord2011 [107]

Answer: (0.9460\ ,\ 0.9500)

Step-by-step explanation:

Given : Population mean : \mu=0.9480

Standard deviation : \sigma=0.0060

Sample size : n=35

Significance level : \alpha=1-0.95=0.05

Critical value = z_{\alpha/2}=\pm1.96

The confidence interval for sample mean is given by :-

\mu\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 0.9480\pm (1.96)\dfrac{0.0060}{\sqrt{35}}

\approx0.9480\pm0.0020=(0.9480-0.0020\ ,\ 0.9480+0.0020)\\\\=(0.9460\ ,\ 0.9500)

Hence, the required interval=  (0.9460\ ,\ 0.9500)

4 0
3 years ago
A factory has four machines that produce the same item. Machines 1 and 2 each produce 20% of the total output, while machines 3
andrezito [222]

Answer:

The answers are a. 0.27 b. 0.2 c. 0.2 d. 0.3 e. 0.3 f. 1

Step-by-step explanation:

Total output = 100% = 1

Total defective = 6% + 5% + 8% + 8% = 27% = 27

a. Prob of defective item = total defective/total output

= 27/100

= 0.27

b. Prob of defective from machine 1 = 6/27 =0.2222

~ 0.2

c. Prob of item defective from machine2 = 5/27 = 0.1852

~0.2

d. Prob of de defective from machine 3 = 8/27 = 0.2963

~0.3

e. Prob of defective from machine 4

= 8/27 = 0.2963

~ 0.3

f. Sum of prob from b-e

0.2 + 0.2 + 0.3 + 0.3

= 1

4 0
3 years ago
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