1) √32 A) 3V2 C) 4V2 B) 4V6 D) 2V6
2 answers:
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We have two widths of the same length plus one length
Let the width be
and the length be 
Perimeter = 2×width + 2×length
(equation 1)
The cost is $5 per foot on the width and $25 per foot on the length
Total cost = (5 × 2 × width) + (25 × length)
(equation 2)
We have two variables that we need to solve, so we will need to use the simultaneous equations method (either elimination or substitution)
Since equation 1 is given
, we can rearrange the equation to make the subject
then substitute this into equation 2
Substitute w = 75 back into 190 = w + l
190 = 75 + l
l = 190 - 75
l = 115
Answer:
Length = 115 feet
Width = 75 feet
Let the width be
Perimeter = 2×width + 2×length
The cost is $5 per foot on the width and $25 per foot on the length
Total cost = (5 × 2 × width) + (25 × length)
We have two variables that we need to solve, so we will need to use the simultaneous equations method (either elimination or substitution)
Since equation 1 is given
then substitute this into equation 2
Substitute w = 75 back into 190 = w + l
190 = 75 + l
l = 190 - 75
l = 115
Answer:
Length = 115 feet
Width = 75 feet