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PIT_PIT [208]
4 years ago
9

A function is created to represent the miles per gallon your car gets. What restrictions would be made to the domain?. a. The do

main would only include integers. b. The domain would only include positive integers. c. The domain would include all real numbers. d. The domain would only include positive numbers.
Mathematics
2 answers:
Ahat [919]4 years ago
4 0

Answer: d. The domain would only include positive numbers.

Step-by-step explanation:

Given: A function is created to represent the miles per gallon your car gets.

Here, the independent variable = the amount of fuel the car gets in gallons.

and the dependent variable = the total miles of car travel .

We know that the domain of a function is a set of all values of independent variable.

Thus, the domain would only include positive numbers because the quantity of fuel in a car is never negative and it can be in fraction .

Hence, D is the right answer.

klasskru [66]4 years ago
4 0
Answer: D) t<span>he domain would only include positive numbers. 

Let's see the definitions of the given options:

1) <em>Integers</em> = positive and negative whole numbers, zero included;
2) <em>Positive integers</em> = positive whole numbers, also known as natural numbers;
3) <em>Real numbers</em> = positive and negative rational numbers, which means any fraction;
4) <em>Positive numbers</em> = any kind of number (whole, fraction or irrational) with the plus sign.

If we want to create a function that represents the miles per gallon, it would be a linear function which describes a direct proportion between the dependent variable (miles) and the independent variable (gallons).

The domain of this function will be the range of possible values for the independent variable (the gallons).

Gallons of gasoline are a real quantity, which can assume any value (whole = 2 gallons, rational = two-thirds of a gallon, irrational = 3.14 gallons), as long as they are positive (we cannot have -2 gallons).
 
Hence, the restriction to the domain of the function will be </span>D) t<span>he domain would only include positive numbers.</span>
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Temka [501]

9514 1404 393

Answer:

  (d)  h = 2A/b

Step-by-step explanation:

Multiply both sides of the equation by the inverse of the coefficient of h.

  A = \dfrac{1}{2}bh=\dfrac{b}{2}\cdot h\\\\\dfrac{2}{b}\cdot A=h\\\\\boxed{h=\dfrac{2A}{b}}

4 0
3 years ago
I know you want to answer this question.
Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

\frac{1}{2} ^{x-4} - 3 = 4^{x-3} - 2

First, convert 4^{x-3} to base 2:

4^{x-3} = (2^{2})^{x-3}

\frac{1}{2} ^{x-4} - 3 = (2^{2})^{x-3} - 2

Next, convert \frac{1}{2} ^{x-4} to base 2:

\frac{1}{2} ^{x-4} = (2^{-1})^{x-4}

(2^{-1})^{x-4} - 3 =  (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{-1})^{x-4} = 2^{-1*(x-4)}

2^{-1*(x-4)} - 3 = (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{2})^{x-3} = 2^{2(x-3)}

2^{-1*(x-4)} - 3 = 2^{2(x-3)} - 2

Apply exponent rule: a^{b+c} = a^{b}a^{c}:

2^{-1(x-4)} = 2^{-1x} * 2^{4}, 2^{2(x-3)} = 2^{2x} * 2^{-6}

2^{-1 * x} * 2^{4} - 3 = 2^{2x} * 2^{-6} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

2^{-1x} = (2^{x})^{-1}, 2^{2x} = (2^{x})^{2}

(2^{x})^{-1} * 2^{4} - 3 = (2^{x})^{2} * 2^{-6} - 2

Rewrite the equation with 2^{x} = u:

(u)^{-1} * 2^{4} - 3 = (u)^{2} * 2^{-6} - 2

Solve u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2:

u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2

Refine:

\frac{16}{u} - 3 = \frac{1}{64}u^{2} - 2

Add 3 to both sides:

\frac{16}{u} - 3 + 3 = \frac{1}{64}u^{2} - 2 + 3

Simplify:

\frac{16}{u} = \frac{1}{64}u^{2} + 1

Multiply by the Least Common Multiplier (64u):

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify:

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify \frac{16}{u} * 64u:

1024

Simplify \frac{1}{64}u^{2} * 64u:

u^{3}

Substitute:

1024 = u^{3} + 64u

Solve for u:

u = 8

Substitute back u = 2^{x}:

8 = 2^{x}

Solve for x:

x = 3

4 0
3 years ago
Using the numbers 3, 2, and 4, which of these problems would have a solution of 4?
Alexeev081 [22]
Pemdas

ok if we look at the first one
exponents first
2^3=8
2^3=8
we have
4*8/8
4*8=32
32/8=4
das is answer


the first one is the answer
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4 years ago
The price of gourmet coffee beans at the corner market has increased 10% per year over the past several years if the current cos
Anarel [89]
$20 because 10% of 40 is 10 and the price now is 40 so 2 years before would have been 20
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Solve and reduce to lowest terms:<br> 6 / 11 x 1 / 3
zysi [14]

Answer:

2/11

Step-by-step explanation:

6/11 x 1/3 =

6/33 =

2/11

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

5 0
3 years ago
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