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jek_recluse [69]
3 years ago
9

I need help please :(​

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
5 0
15x + 11x + 8x+5 = 180

34x + 5 = 180

34x = 180-5

34x = 175

x = 5.147


by substitution each value by of x by 5




75 + 55 + 45 = 175
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Which viewing window boundaries would allow you to see all the intercepts and the maximum, as closely as possible, for the funct
tino4ka555 [31]

Answer:

The minimum window boundary for the x-axis should be

✔ –4

The maximum window boundary for the x-axis should be

✔ 7

The minimum window boundary for the y-axis should be

✔ –1

The maximum window boundary for the y-axis should be

✔ 23

Step-by-step explanation:

edge 2021

5 0
3 years ago
A survey of 35 individuals who passed the seven exams and obtained the rank of Fellow in the actuarial field finds the average s
arsen [322]

Answer:

150000-2.032\frac{15000}{\sqrt{35}}=144847.94    

150000+2.032\frac{15000}{\sqrt{35}}=155152.06

So on this case the 95% confidence interval would be given by (144847.94;155152.06)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=150000 represent the sample mean

\mu population mean (variable of interest)

s=15000 represent the sample standard deviation

n=35 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=35-1=34

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,34)".And we see that t_{\alpha/2}=2.032

Now we have everything in order to replace into formula (1):

150000-2.032\frac{15000}{\sqrt{35}}=144847.94    

150000+2.032\frac{15000}{\sqrt{35}}=155152.06

So on this case the 95% confidence interval would be given by (144847.94;155152.06)    

3 0
4 years ago
Please help in finding the radians in degrees!
ohaa [14]

Answer:

  225°

Step-by-step explanation:

Multiply radians by 180°/π to get degrees.

  (5π/4)×(180°/π) = (5/4)(180°) = 225°

6 0
3 years ago
Perry made a wooden cube with an edge length of 8.5 inches in shop class. He painted half the faces of the cube red and the othe
horrorfan [7]
I think 3a^2 is surface area
3(8.5)^2
216.75 inches^2

6 0
4 years ago
Read 2 more answers
PLEASE HELP WILL MARK BRAINLIEST
Pavel [41]

Answer:

Apply the sine theorem in triangle ABC:

sin C = AB/AC = 4/5

=> C  = arcsin(4/5) = 53.13 deg

As shown in picture, AB//CD. Using the same side interior angles theorem:

=> angle BCD = angle ABC = 90 deg

=> angle ACD = 90 - angle ACB = 90 - C = 90 - 53.13 = 36.87 deg

Apply the cosine theorem in triangle ACD:

cos C = AC/CD

=> CD = AC/cos C = 5/cos(36.87) = 5/0.8 = 6.25

=> Option C is correct

Hope this helps!

:)

6 0
3 years ago
Read 2 more answers
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