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Tomtit [17]
3 years ago
9

Here is a table of values y=f(x).

Mathematics
1 answer:
Mariulka [41]3 years ago
4 0

A. <u>False.</u> The range of f(x) is the set of values it can produce. In the table, f(x) produces values from 0 to 3. However, the range of all real numbers is all rational numbers, basically from -\infty to \infty, not just a few numbers in-between. So, the range of f(x) is not all real numbers.

B.  <u>True.</u> Looking at the table, when x=-3, f(x)=2. This is another way of saying that f(-3)=2, which is what B is saying.

C. <u>True.</u> The domain of f(x) is the set of values of x that produce some output in f(x). Looking at the table, all of the x values listed on it are in the set \{-5, -3, 0, 2, 6, 7, 9, 10, 13\}, which is what C is saying.

D. <u>False.</u> Looking at the table, when x=0, f(x)=3. This is another way of saying that f(0)=3, which is <em>not </em>what B is saying.

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(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
x < \frac{5}{3}
\frac{5}{3} < x < 5
x > 5
Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

3 0
3 years ago
A student deposits the same amount of money into her bank account each week. At the end of the second week she has $30 in her ac
Nonamiya [84]
The student will have $135 in her bank account at the end of the ninth week. You can fine this out by finding out the amount she deposits a week and to do this you would take the $30 and divide it by 2 because she had $30 at the end of the second week. 
30/2=15
So you see that the student deposits $15 each week, so to find out how much money she will have in 9 weeks you will multiply her $15 by 9.
15x9=135
So the student will have $135 at the end of the ninth week. 
6 0
2 years ago
Help i’m begging plsss
olga_2 [115]

Answer:

x=8

Step-by-step explanation:

Given

AB||CD

\angle ABC = 5x + 50

\angle BCD = 7x + 34

Required

Find x

If AB||CD i.e. If AB is parallel to CD, then

\angle ABC = \angle BCD

Substitute values for ABC and BCD

5x + 50 = 7x + 34

Collect Like Terms

5x - 7x = -50 + 34

-2x = -16

Multiply through by -\frac{1}{2}

-\frac{1}{2} * -2x = -16 * -\frac{1}{2}

\frac{1}{2} * 2x = 16 * \frac{1}{2}

\frac{2x}{2} = \frac{16}{2}

x = \frac{16}{2}

x=8

3 0
2 years ago
What number has 10 tents 0 ones?
alexandr402 [8]

the answer would be 100

8 0
3 years ago
4/5 x = 8 i need to show my work​
Anika [276]

Answer:

x=10

Step-by-step explanation:

I'm assuming you needed to solve for x. Here is how you do it:

first, divide both sides by 4/5 to get x by itself.

this will give you x=8 divided by 4/5.

To solve 8 divided by 4/5 you do keep switch flip.

keep the first number (8), switch the sign (division to multiplication), and flip the other fraction (4/5 to 5/4) then you can just multiply across the top (8/1 *5/4) which equals 40/4. This simplified is 10

4 0
2 years ago
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