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olasank [31]
3 years ago
5

The rectangular bed of a truck is 1 9⁄10 meters long, 1 1⁄2 meters wide, and 1⁄2 meter tall. What is the volume of the truck's b

ed?
Mathematics
2 answers:
Tom [10]3 years ago
6 0

Answer:

1 17/40 m³

Step-by-step explanation:

1.9 × 1.5 × 0.5

= 1.425 m³

19/10 × 3/2 × 1/2

= 57/40

= 1 17/40 m³

SpyIntel [72]3 years ago
5 0

Answer:

1 17/40 m^3

Step-by-step explanation:

Volume = l*w*h

             = 1 9/10 * 1 1/2 * 1/2

Changing the mixed numbers to improper fractions

1 9/10 = (10*1+9) /10 = 19/10

1 1/2 = (2*1+1)/2 = 3/2

1/2 = 1/2

V = 19/10* 3/2*1/2

  =57/40

Changing this back to a mixed number

40/40 + 17/40

1 17/40

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3 years ago
A sequence is defined by the formula f(n + 1) = f(n) – 3. If f(4) = 22, what is f(1)?
julsineya [31]

f(n) = f(n+1) +3

f(1) = f(2) +3

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                             hope it helps

5 0
3 years ago
Read 2 more answers
How can you check that this answer is correct? 5,244 = 6= 874​
nignag [31]

I think you meant 5,244 ÷ 6 = 874.

Answer/Step-by-step explanation:

We can check if this 5,244 ÷ 6 = 874 is correct by doing it opposite.

Since it 5,244 divide 6 we can do 874 x 6.

  \left[8   7   4] \\

×    [6]

======

+ 5244

=======

5244

Hence, this answer is correct.

[RevyBreeze]

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2 years ago
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GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
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