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3 years ago

A sequence is defined by the formula f(n + 1) = f(n) – 3. If f(4) = 22, what is f(1)?

Mathematics

2 answers:

arsen [322]3 years ago

7 0

It's C

bysiuhaojlkejvhbrusaoilwhy20frick

julsineya [31]3 years ago

5 0

f(n) = f(n+1) +3

f(1) = f(2) +3

f(2) =f(3) +3

f(3) = f(4) +3

So f(1) = f(n) + 3* (n-1)

Put n=4 here so you found

f(1) = f(4) + 3* 3

= 22 +9

=31 ans

hope it helps

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8. Solve the system of equations using substitution.

Elodia [21]

Answer:

Step-by-step explanation:

In order to solve this we need to plug in the answer choices and make sure they work for BOTH answers!

Let us start with option A. (6,3) 3 = 4(6) + 6 = 3 = 30 This is automaticly wrong because 3 doesnt equal 30. There is no need to try it on the second equation since the first one was wrong.

Next answer choice, B (3,6) 6 = 2(3) = 6=6. The second equation works perfect for this. Now we have to make sure that it works for the first one as well. 6 = 4(3) + 6 = 6 = 18 which is wrong.

Next, C. (1,2) 2 = 2(1) = 2=2 Right now lets check the other equation.

2 = 4(1) + 6 = 2=10. Wrong

Last, D. (-3, -6) -6 = 2(-3) = -6 = -6 Right now lets check the other equation.

-6 = 4(-3) + 6 = -6 = -6. CORRECT. Answer choice D works for both equations.

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3 years ago

Question 3

Fiesta28 [93]

Answer: y = -6x + 2

m = y_2 - y_1
/ x_2 - x_1

-10 - 8
/ 2 - (-1)

= -18/3 = -6

m (slope) = -6

y = mx + b
y = -6x +b

Find b using (-1,8)
y = -6x +b
8 = -6(-1) + b
8 = 6 + b
-6 -6
2 = b

Final answer: y = -6x + 2

To check using one of the points: (-1,8) or (2,-10)
y = -6x + 2
-10 = -6(2) + 2
-10 = -12 + 2
-10 = -10
This is a true statement.

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2 years ago

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2 years ago

En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand

Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

$\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}$ (1)

Donde:

$F_{1}$ - Fuerza experimentada por el elefante, medida en newtons.

$F_{2}$ - Fuerza aplicada sobre el plato pequeño, medida en newtons.

$A_{1}$ - Área del plato grande, medida en metros cuadrados.

$A_{2}$ - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

$F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}$

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

$F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g$ (2)

Donde:

$D_{1}$ - Diámetro del plato grande, medido en centímetros.

$D_{2}$ - Diámetro del plato pequeño, medido en centímetros.

$m$ - Masa del elefante, medida en kilogramos.

$g$ - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que $D_{1} = 0.75\,m$ , $D_{2} = 0.13\,m$ , $m = 2900\,kg$ y $g = 9.807\,\frac{m}{s^{2}}$ , entonces la fuerza a aplicar al émbolo pequeño es:

$F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$F_{2} = 854.473\,N$

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

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